__FeS2 + __O2 → __Fe2O3 + __SO2 When fool’s gold, iron (IV) sulfide reacts with oxygen it forms ferric oxide and sulfur dioxide. If a 21.63 gram nugget of fool’s gold is reacted with 1.05 moles of oxygen, How much excess reactant was present?
__FeS2 + __O2 → __Fe2O3 + __SO2 When fool’s gold, iron (IV) sulfide reacts with oxygen it forms ferric oxide and sulfur dioxide. If a 21.63 gram nugget of fool’s gold is reacted with 1.05 moles of oxygen, How much excess reactant was present?
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.75PAE
Question
__FeS2 + __O2 → __Fe2O3 + __SO2
When fool’s gold, iron (IV) sulfide reacts with oxygen it forms ferric oxide and sulfur dioxide. If a 21.63 gram nugget of fool’s gold is reacted with 1.05 moles of oxygen, How much excess reactant was present?
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