Phosphorus reacts with oxygen to form diphosphorus pentoxide, P₂O5. 4 P(s) + 50₂(g) 2P₂05 (s) How many grams of P₂O5 are formed when 3.59 g of phosphorus reacts with excess oxygen? Show the unit analysis used for the calculation by placing the correct components into the unit-factor slots. 32 3.59 g P x 141.94 g P₂O5 4 mol P 5 mol O₂ X Answer Bank 32.00 g 0₂ 1 mol O₂ 1 mol P₂0, 2 mol P₂O5 1 mol P 30.97 g P = g P₂05
Phosphorus reacts with oxygen to form diphosphorus pentoxide, P₂O5. 4 P(s) + 50₂(g) 2P₂05 (s) How many grams of P₂O5 are formed when 3.59 g of phosphorus reacts with excess oxygen? Show the unit analysis used for the calculation by placing the correct components into the unit-factor slots. 32 3.59 g P x 141.94 g P₂O5 4 mol P 5 mol O₂ X Answer Bank 32.00 g 0₂ 1 mol O₂ 1 mol P₂0, 2 mol P₂O5 1 mol P 30.97 g P = g P₂05
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Phosphorus reacts with oxygen to form diphosphorus pentoxide, P₂O5.
4 P(s) + 50₂(g)
2 P₂O5 (s)
2
How many grams of P₂O5 are formed when 3.59 g of phosphorus reacts with excess oxygen? Show the unit analysis used for
the calculation by placing the correct components into the unit-factor slots.
3.59 g P x
141.94 g P₂O5
4 mol P
5 mol O₂
E
Answer Bank
32.00 g 0₂
1 mol O₂
36
1 mol P₂05
2 mol P₂O5
1 mol P
30.97 g P
= g P₂05](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb0d79c4c-40ce-427b-b4a0-26ffd9f423cd%2F7ea9ffe5-0530-4992-9949-b8a95a01e429%2F7dtpe7j_processed.png&w=3840&q=75)
Transcribed Image Text:Phosphorus reacts with oxygen to form diphosphorus pentoxide, P₂O5.
4 P(s) + 50₂(g)
2 P₂O5 (s)
2
How many grams of P₂O5 are formed when 3.59 g of phosphorus reacts with excess oxygen? Show the unit analysis used for
the calculation by placing the correct components into the unit-factor slots.
3.59 g P x
141.94 g P₂O5
4 mol P
5 mol O₂
E
Answer Bank
32.00 g 0₂
1 mol O₂
36
1 mol P₂05
2 mol P₂O5
1 mol P
30.97 g P
= g P₂05
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