9:20 am HW4, Ch14 Q1. at: Initial Сваде Equil H₂(g) + [2(g) = 2 HI(g), K₂ = 54.3 at 430°C 0.40 Inital CH2=0.40M 32-58/59-23 O N 2 x K₂=54.3 = O * א x (0.40-22)² (*) (*) <-2x 0.40-2X and Solve for x find equilibrium cone of each species
9:20 am HW4, Ch14 Q1. at: Initial Сваде Equil H₂(g) + [2(g) = 2 HI(g), K₂ = 54.3 at 430°C 0.40 Inital CH2=0.40M 32-58/59-23 O N 2 x K₂=54.3 = O * א x (0.40-22)² (*) (*) <-2x 0.40-2X and Solve for x find equilibrium cone of each species
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![im
022, 9:20 am
HW4, Ch14
Q1.
Hint:
Initial
Change
Equil
32:56/59-23
F5
H₂(g) + [₂(g) = 2 HI(g), K₂ = 54.3 at 430°C
Inital CH2=0.40M
0.40
O
O
K₂=54.3 =
13
Z
x
FO
x
x
(0.40-22)²
(*) (*)
MacBook Air
F7
▶11
-2x
0.40-2X
and
Solve for x
find equilibrium
cone of each Species](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff7e09213-2f94-4c3d-b797-91e69c6a2f67%2Fff543743-6f45-4cab-82d5-40755adb45af%2Fu1xpbj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:im
022, 9:20 am
HW4, Ch14
Q1.
Hint:
Initial
Change
Equil
32:56/59-23
F5
H₂(g) + [₂(g) = 2 HI(g), K₂ = 54.3 at 430°C
Inital CH2=0.40M
0.40
O
O
K₂=54.3 =
13
Z
x
FO
x
x
(0.40-22)²
(*) (*)
MacBook Air
F7
▶11
-2x
0.40-2X
and
Solve for x
find equilibrium
cone of each Species
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