9:12 STARTING AMOUNT ADD FACTOR x( ) A liquid in the lab has a density of 1.17 g/cm³. What is the volume in liters of 3.02 kg of the liquid? 3.53 1 3.02 2.58 3.53 x 10³ 10 2.58 x 10³ Question 25 of 40 0.001 1.17 cm³ mL L kg g/cm³ g X .. LTE ANSWER Submit RESET 5

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Density and Volume Calculation Exercise**

**Question 25 of 40**

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**Problem Statement:**

A liquid in the lab has a density of 1.17 g/cm³. What is the volume in liters of 3.02 kg of the liquid?

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**Interactive Prompt:**

- There are interactive sections where you can input the values to solve the problem:
  - **Starting Amount**: Enter the given mass of the liquid (3.02 kg).
  - **Multiplication Section**: This area is used to input the conversion factors and calculators suitable for solving the problem.

---

**Available Values for Calculation**:

- **Blue Buttons**:
  - 3.53
  - 1
  - 3.02
  - 2.58
  - 3.53 x 10³
  - 10³
  - 2.58 x 10³
  - 0.001
  - 1.17

- **Red Buttons**:
  - cm³
  - mL
  - L
  - kg
  - g/cm³
  - g

**Functional Buttons**:
  - **x ()**: Adds a multiplication factor.
  - **= [ ]**: Computes the answer.
  - **Reset**: Clears all input fields and starts fresh.

**Instructions**:

1. Identify the known values:
   - Density: 1.17 g/cm³
   - Mass: 3.02 kg

2. Convert the mass from kg to g:
   - Use the conversion factor: 1 kg = 1000 g
   - 3.02 kg = 3.02 x 1000 = 3020 g

3. Use the density formula to find the volume:
   - Density (ρ) = mass (m) / volume (V)
   - Rearrange to find Volume: V = m / ρ
   - Substitute the known values: V = 3020 g / 1.17 g/cm³ ≈ 2580.34 cm³

4. Convert cm³ to liters (since 1 mL = 1 cm³ and 1000 mL = 1 L):
   - Volume in liters: 2580.34 cm³ / 1000 ≈ 2.580 L

The calculated volume of the liquid is approximately **2.580
Transcribed Image Text:**Density and Volume Calculation Exercise** **Question 25 of 40** --- **Problem Statement:** A liquid in the lab has a density of 1.17 g/cm³. What is the volume in liters of 3.02 kg of the liquid? --- **Interactive Prompt:** - There are interactive sections where you can input the values to solve the problem: - **Starting Amount**: Enter the given mass of the liquid (3.02 kg). - **Multiplication Section**: This area is used to input the conversion factors and calculators suitable for solving the problem. --- **Available Values for Calculation**: - **Blue Buttons**: - 3.53 - 1 - 3.02 - 2.58 - 3.53 x 10³ - 10³ - 2.58 x 10³ - 0.001 - 1.17 - **Red Buttons**: - cm³ - mL - L - kg - g/cm³ - g **Functional Buttons**: - **x ()**: Adds a multiplication factor. - **= [ ]**: Computes the answer. - **Reset**: Clears all input fields and starts fresh. **Instructions**: 1. Identify the known values: - Density: 1.17 g/cm³ - Mass: 3.02 kg 2. Convert the mass from kg to g: - Use the conversion factor: 1 kg = 1000 g - 3.02 kg = 3.02 x 1000 = 3020 g 3. Use the density formula to find the volume: - Density (ρ) = mass (m) / volume (V) - Rearrange to find Volume: V = m / ρ - Substitute the known values: V = 3020 g / 1.17 g/cm³ ≈ 2580.34 cm³ 4. Convert cm³ to liters (since 1 mL = 1 cm³ and 1000 mL = 1 L): - Volume in liters: 2580.34 cm³ / 1000 ≈ 2.580 L The calculated volume of the liquid is approximately **2.580
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