9.35 A random sample of size n1 =normal population with a standard deviation ơ1 =has a mean ã1 = 80. A second random sample of sizen2 = 36, taken from a different normal population witha standard deviation o2 =a 94% confidence interval for µi – µ2.= 25, taken from a= 5,3, has a mean 2 = 75. Find

We want to find a 94% confidence interval

Answered: 9.35 A random sample of size n1 =…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Give a 90% confidence interval, for μ1−μ2μ1-μ2 given the following information. n1=20, x¯1=2.95, s1=0.7n2=30, ¯x2=2.76 , s2=0.75 __±___ Use Technology Rounded to 2 decimal places.
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The average number of miles a person drives per day is 24. A researcher wishes to see if people over age 60 drive less than 24 miles per day. She selects a random sample of 40 drivers over the age of 60 and finds that the mean number of miles driven is 22.7. The population standard deviation is 2.9 miles. At =α0.01, is there sufficient evidence that those drivers over 60 years old drive less than 24 miles per day on average? Assume that the variable is normally distributed. Use the critical value method with tables. State the hypotheses and identify the claim with the correct hypothesis.
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. The mean braking distance for SUVs equipped with tires made with compound 1 is 65 feet, with a population standard deviation of 13.6. The mean braking distance for SUVS equipped with tires made with compound 2 is 69 feet, with a population standard deviation of 8.5. Suppose that a sample of 55 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ₁ be the true mean braking distance corresponding to compound 1 and μ₂ be the true mean braking distance corresponding to compound 2. Use the 0.05 level of significance. Step 3 of 5 Find the p-value associated with the test statistic. Round your answer to four decimal places. Answer How to enter your answer (opens in…
A random sample of 23 bags of apples (marked as 10 pounds each) received by a large grocery chain tested out as having a mean of 9.2 pounds with a variance of 2.56 pounds. Test whether the true mean of all bags is under 10 pounds. Set up hypotheses. Perform the appropriate test by showing your formula. Interpret the results using a Type I (alpha) error of .05. Also provide the p value here. Also construct a 95% confidence interval around your sample mean (X bar) that should contain the true mean (mu). Also interpret this interval.
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. The mean braking distance for SUVS equipped with tires made with compound 1 is 68 feet, with a population standard deviation of 13.9. The mean braking distance for SUVs equipped with tires made with compound 2 is 73 feet, with a population standard deviation of 13.7. Suppose that a sample of 72 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVS equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ, be the true mean braking distance corresponding to compound 1 and μ₂ be the true mean braking distance corresponding to compound 2. Use the 0.05 level of significance. Step 1 of 5: State the null and alternative hypotheses for the test.
A recent study showed that the average number of sticks of gum a person chews in a week is 11. A college student believes that the guys in his dormitory chew a different amount of gum in a week. He conducts a study and samples 19 of the guys in his dorm and finds that on average they chew 13 sticks of gum in a week with a standard deviation of 1.6. Test the college student's claim at αα=0.01.
Suppose a marketing company randomly surveyed 404 households and found that in 214 of them, the woman made the majority of the purchasing decisions. Construct a 90% confidence interval for the population proportion of households where the women make the majority of the purchasing decisions.p'=α2=zα2=Margin of Error: E=We are 90% confident that the proportion of households in the population where women make the majority of purchasing decisions is between___ and ___.
A random sample of 10 subjects have weights with a standard deviation of 10.9654 kg what is the variance of their weights be sure to include the appropriate units with the result
A sample of size 43 with = 65.5 and s = 11.3 is used to estimate a population mean μ. Find the 95% confidence interval for u. Round the answers to one decimal place. <με LI
Independent samples of size n1 = 25 and n2 = 36 are taken from two normal populations with knownstandard deviations of σ1 = 5.5 and σ2 = 4.2. e sample means are x¯1 = 13.6 and x¯2 = 19.2. Find a95% confidence interval for µ1 − µ2.
6.05 Based on a random sample of size n = 40, the 95% confidence interval for the true mean weight in mg for beans of a certain type is (229.7,233.5). Obtain the 99% confidence interval.

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