According to the U.S. Department of Agriculture, the average American consumed an average of 39 pounds of cheese in 2018. The cheese company Sargento claims the average amount of cheese consumed by Americans is different now than in 2018 and obtains a random sample of 35 Americans and finds the mean to be 38.2 pounds with a standard deviation of 2.49 pounds. Using the Minitab printout below, test Sargento’s claim at α = 0.10. (Show all six steps.)
According to the U.S. Department of Agriculture, the average American consumed an average of 39 pounds of cheese in 2018. The cheese company Sargento claims the average amount of cheese consumed by Americans is different now than in 2018 and obtains a random sample of 35 Americans and finds the mean to be 38.2 pounds with a standard deviation of 2.49 pounds. Using the Minitab printout below, test Sargento’s claim at α = 0.10. (Show all six steps.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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According to the U.S. Department of Agriculture, the average American consumed an average of 39 pounds of cheese in 2018. The cheese company Sargento claims the average amount of cheese consumed by Americans is different now than in 2018 and obtains a random sample of 35 Americans and finds the mean to be 38.2 pounds with a standard deviation of 2.49 pounds. Using the Minitab printout below, test Sargento’s claim at α = 0.10. (Show all six steps.)
step 1) Ho:
step 2) Ha:
step 3)
step 4)
step 5)
step 6)
Transcribed Image Text:WORKSHEET 1
One-Sample T
Descriptive Statistics
N Mean StDev SE Mean 95% Cl for u
35 38.200 2.490
0.421 (37.345, 39.055)
Hi population mean of Sample
Test
Ho: H = 39
H;: µ # 39
Null hypothesis
Alternative
hypothesis
T-Value P-Value
-1.90
0.066
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