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9.20 Calculate the standard deviation for the x coordinate of a harmonic oscillator at v= 1. Since (x) = 0, it is only necessary to calculate (x²).

9.20 Calculate the standard deviation for the x coordinate of a harmonic oscillator at v= 1. Since (x) = 0, it is only necessary to calculate (x²).

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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9.20 Calculate the standard deviation for the x coordinate of a harmonic oscillator at v = 1. Since (x) = 0, it is only necessary to calculate (x²).
Transcribed Image Text:9.20 Calculate the standard deviation for the x coordinate of a harmonic oscillator at v = 1. Since (x) = 0, it is only necessary to calculate (x²).
#20 dy dx 36 4₁ (x) = √2 72 (+) S = 2/x = 2 a = x = 4/x+ 2 2 • [" (12/01) * h) <x ²) = √² 4 * (x) + x². P₁ (x) dx = √2/2 d 18 F a VIT 3/2 8 (*) 18 84 xe 3√T 3√√a² 14 3√ за 5/2 1₂ 2. -ax² dx xe 2 -dx 2 4 -ax e e A JANA MA -ax 29 a + -ax xe 2a 2 -ax = 2 xe
Transcribed Image Text:#20 dy dx 36 4₁ (x) = √2 72 (+) S = 2/x = 2 a = x = 4/x+ 2 2 • [" (12/01) * h) <x ²) = √² 4 * (x) + x². P₁ (x) dx = √2/2 d 18 F a VIT 3/2 8 (*) 18 84 xe 3√T 3√√a² 14 3√ за 5/2 1₂ 2. -ax² dx xe 2 -dx 2 4 -ax e e A JANA MA -ax 29 a + -ax xe 2a 2 -ax = 2 xe
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