9.14 The following measurements were recorded for the drying time, in hours, of a certain brand of latex paint: 3.4 2.5 4.8 2.9 3.6 2.8 3.3 5.6 3.7 2.8 5.2 4.4 4.0 3.0 4.8 Assuming that the measurements represent a random sample from a normal population, find a 95% predic- tion interval for the drying time for the next trial of the paint.
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- Given a normal distribution with µ = 20 and o = 5, find the normal curve area to %3D the right of x = 18. ( 0.2743 0.6554 O 0.2119 0.8413Below is a graph of a normal distribution with mean =μ1 and standard deviation =σ4. The shaded region represents the probability of obtaining a value from this distribution that is between 3and 5. 0.1 0.2 0.3 0.4 X 1 3 5 Shade the corresponding region under the standard normal density curve below. 0.1 0.2 0.3 0.4 Z 1 2 3 4 5 6 7 8 9 -1 -2 -3 -4 -5 -6 -7 -8 -9Find the corresponding z-score for a sample of n = 16 and M = 38 taken from a population with a mean of μ= 40 and σ = 8.
- You obtain a t comp of .975 in a two sample independent t test with alpha at .05. Is it significant?A food manufacturer claims that eating its new cereal as part of a daily diet lowers total blood cholesterol levels. The table shows the total blood cholesterol levels (in milligrams per deciliter of blood) of seven patients before eating the cereal and after one year of eating the cereal as part of their diets. Use technology to test the mean difference. Assume the samples are random and dependent, and the population is normally distributed. At α=0.05, can you conclude that the new cereal lowers total blood cholesterol levels? Patient 1 2 3 4 5 6 7 Total Blood Cholesterol (Before) 215 225 235 240 255 260 225 Total Blood Cholesterol (After) 214 222 240 237 254 257 222 Let the blood cholesterol level before eating the cereal be population 1. Let the blood cholesterol level after eating the cereal be population 2. Identify the null and alternative hypotheses, where μd=μ1−μ2. Choose the correct…Suppose in a local Kindergarten through 12th grade (K -12) school district, 49% of the population favor a charter school for grades K through 5. A simple random sample of 144 is surveyed. a. Find the mean and the standard deviation of X of B(144, 0.49). Round off to 4 decimal places. O = b. Now approximate X of B(144, 0.49) using the normal approximation with the random variable Y and the table. Round off to 4 decimal places. Y - N( c. Find the probability that at most 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X 75) - P(Y > a (Z > e. Find the probability that exactly 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X = 81) - P(Suppose in a local Kindergarten through 12th grade (K -12) school district, 49% of the population favor a charter school for grades K through 5. A simple random sample of 144 is surveyed. a. Find the mean and the standard deviation of X of B(144, 0.49). Round off to 4 decimal places. O = b. Now approximate X of B(144, 0.49) using the normal approximation with the random variable Y and the table. Round off to 4 decimal places. Y - N( c. Find the probability that at most 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X 75) - P(Y > a (Z > e. Find the probability that exactly 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X = 81) - P(A manufacturer claims that the thickness of the metal plates it produces is 2.0mm. A quality control specialist regularly checks this claim. On one production run, he took a random sample of n = 8 pieces of metal plates and measured their thickness. He obtained: 2.2 2.0 1.9 1.8 2.1 2.5 2.3 2.3 Test the hypothesis of quality control specialists that HO: μ = 2.0 at 0.01 level of significance. Use 6 steps method.Show all tabulated computations.A normal population sample has a standard deviation of 16 and sample size m = 100 . The rejection region for testing H0: ? = 5 ?????? Ha: ? = k is that X > k − 2. Find the value of k that will allow P(X > k− 2|H0: ? = 5 )=0.0228.7:40 A myopenmath.com Women are recommended to consume 1850 calories per day. You suspect that the average calorie intake is different for women at your college. The data for the 12 women who participated in the study is shown below: 2021, 2025, 2021, 1853, 2025, 2102, 1888, 1963, 1850, 1897, 1808, 2011 Assuming that the distribution is normal, what can be concluded at the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: Select an answer Н: ? V Select an answer c. The test statistic ? ▼ (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is (? v f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... The data suggest that the population mean calorie intake for women at your college is not significantly different from 1850 at a = 0.01, so there is insufficient evidence to…Use SAS output for a random sample of size 20 to answer the following questions. Regression of yon X and X₂ Regression of y on X₁ X₁₂, and X₂ 3 F1.17, 0.99 = 8.40 F3,16, 0.99 = 5.29 F1.17, 0.95 = 4.45 F3,16, 0.95 = 3.24 d) is the overall regression of the model that includes the three predictors significant? Use a=0.01 O Reject the null hypothesis O Do not reject the null hypothesis Source Model Error Parameter Intercept x1 x2 x3 Corrected Total 19 1855.20200 Source DF 1 1 1 x1 x2 x3 Number of Observations Read 20 Number of Observations Used 20 R-Square Coeff Var Root MSE 0.818318 22.31297 Analysis of Variance x1 x2 x3 Sum of Mean Source Model Error DF Squares 2 1317.79841 658.89921 17 537.40359 31.61198 Square F Value Pr > F 20.84 F 3 1518.144941 506 048314 24.02 0001 337.067069 21.066066 1855.202000 16 Corrected Total 19 F2,17, 0.99 = 6.11 F4.16, 0.99 = 4.77 F2,17, 0.95 = 3.59 F4.16, 0.95 = 3.01Samples of n = 9 items each are taken from a process at regular intervals. A quality characteristic is measured, and x and R control charts are made based on 2.7 sigma limits and used the following summaries: 50 50 Ex = 2000 and R, = 200 %3D Assume that the quality characteristic is normally distributed. 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