9. Use Newton's law of universal gravitation to calculate the weight of a 70-kg person standing on the surface of the earth. Then repeat the calculation by using W = mg and compare your two results. Mass of the earth= 5.972 * 10²4 kg Radius of the earth = 6371 km Acceleration due to gravity =g = 9.81 m/s² G= 6.673 * 10-¹1 m³/(kg.s²) R me m = 70 kg Po

9. Use Newton's law of universal gravitation to calculate the weight of a 70-kg person standing on the surface of the earth. Then repeat the calculation by using W = mg and compare your two results. Mass of the earth= 5.972 * 10²4 kg Radius of the earth = 6371 km Acceleration due to gravity =g = 9.81 m/s² G= 6.673 * 10-¹1 m³/(kg.s²) R me m = 70 kg Po

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Example 11. Calculate the mass of the earth from the following data. Radius of earth R = 6x10® cm = 6 × 10° m. Acceleration due to gravity = 9.8 ms-2 Gravitational constant G = 6.67 × 10-lI Nm³/kg².
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Part A The value of Gmdre", where me is the mass of the earth, r, is the radius of the earth, and G is the universal gravitational constant is (enter your answer with three significant figures) ΑΣΦ IXI X•10n -11 6.67 101 m/? Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
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