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8. The approximate gravitational force between the earth and an individual with mass 60 kg is 2.39 - 1010 I(d) = Newtons, where d is the distance (in km) from the center of the earth to the d 1.195 - 10 individual. The equivalent force on a 3-kg textbook is T(d) = from the center of the earth to the surface is roughly 6, 371 kilometers. The individual is on a rocket such that their distance from the center of the earth is D(t) = 0.00131 – 0.00088t + 6371 kilometers, t seconds after launch. Newtons. The distance (a) Compute (I+T)(6371). Write a sentence interpreting this value within the applied context. (b) Compute (I/T) (6371). Write a sentence interpreting this value within the applied context. (c) Compute (I o D)(120). Write a sentence interpreting this value within the applied context.

8. The approximate gravitational force between the earth and an individual with mass 60 kg is 2.39 - 1010 I(d) = Newtons, where d is the distance (in km) from the center of the earth to the d 1.195 - 10 individual. The equivalent force on a 3-kg textbook is T(d) = from the center of the earth to the surface is roughly 6, 371 kilometers. The individual is on a rocket such that their distance from the center of the earth is D(t) = 0.00131 – 0.00088t + 6371 kilometers, t seconds after launch. Newtons. The distance (a) Compute (I+T)(6371). Write a sentence interpreting this value within the applied context. (b) Compute (I/T) (6371). Write a sentence interpreting this value within the applied context. (c) Compute (I o D)(120). Write a sentence interpreting this value within the applied context.

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8. The approximate gravitational force between the earth and an individual with mass 60 kg is 2.39 - 1010 I(d) Newtons, where d is the distance (in km) from the center of the earth to the 1.195 · 10° individual. The equivalent force on a 3-kg textbook is T(d) = from the center of the earth to the surface is roughly 6, 371 kilometers. The individual is on a rocket such that their distance from the center of the earth is D(t) = 0.00131 – 0.00088t + 6371 kilometers, t seconds after launch. Newtons. The distance (a) Compute (I+T)(6371). Write a sentence interpreting this value within the applied context. (b) Compute (I/T) (6371). Write a sentence interpreting this value within the applied context. (c) Compute (I o D)(120). Write a sentence interpreting this value within the applied context.
Transcribed Image Text:8. The approximate gravitational force between the earth and an individual with mass 60 kg is 2.39 - 1010 I(d) Newtons, where d is the distance (in km) from the center of the earth to the 1.195 · 10° individual. The equivalent force on a 3-kg textbook is T(d) = from the center of the earth to the surface is roughly 6, 371 kilometers. The individual is on a rocket such that their distance from the center of the earth is D(t) = 0.00131 – 0.00088t + 6371 kilometers, t seconds after launch. Newtons. The distance (a) Compute (I+T)(6371). Write a sentence interpreting this value within the applied context. (b) Compute (I/T) (6371). Write a sentence interpreting this value within the applied context. (c) Compute (I o D)(120). Write a sentence interpreting this value within the applied context.
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Given that,Force between earth and an Individual 60 kgId=2.39×1010d2 NewtonForce between Earth and a text book 3 kg)Td=1.195×109d2 Newtona.) I+T6371=2.39×101063712 Newton+1.195×10963712 Newton=1096371223.9+1.195=618.2611 NewtonAnswer: 618.261 Newton is the sum of force with which earth is pulling down a 60kg individual and 3kg textbok on the surface

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