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9. Given a signal S) as shown below. Its FT F(@) is to be: Q F(a) = 20 B. F(m) = 20( sinc(Sa-2)+sinc(Sar + 2)) C. F(@) = 20( sinc(5e-x/2)+ sinc(sinc(Sa +=/2) sinc(10-+ sinc(10e+ 20

9. Given a signal S) as shown below. Its FT F(@) is to be: Q F(a) = 20 B. F(m) = 20( sinc(Sa-2)+sinc(Sar + 2)) C. F(@) = 20( sinc(5e-x/2)+ sinc(sinc(Sa +=/2) sinc(10-+ sinc(10e+ 20

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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p 2:19 D183% *,„ll & O 1 h 100 Jo 9. Given a signal f(t) as shown below, Its FT F(a) is to be: a, F(@) = 20 sinc(10a-)+ sinc(10+ B. F(@) = 20( sinc(Sa» – 2) +sinc(Sas + 2) C. F() = 20( sinc(Se-/2) + sinc(sinc(Sa + /2)) 20 D. F() = rect(St -5+ rect(St + -10
Transcribed Image Text:p 2:19 D183% *,„ll & O 1 h 100 Jo 9. Given a signal f(t) as shown below, Its FT F(a) is to be: a, F(@) = 20 sinc(10a-)+ sinc(10+ B. F(@) = 20( sinc(Sa» – 2) +sinc(Sas + 2) C. F() = 20( sinc(Se-/2) + sinc(sinc(Sa + /2)) 20 D. F() = rect(St -5+ rect(St + -10
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