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9. Given a signal f1) as shown below. Its FT F(0) is to be: Q F(a) = 20 sinc(10 -+sinc(10a+5 B. F(@) = 20( sinc(Sa-2)+ sinc(Sa + 2)) C. F(m) = 20( sinc(Se-/2)+sinc(sinc(Sa +/2) rect($t -5+reci(St + 20 D. F(@) = - -10 -3 10

9. Given a signal f1) as shown below. Its FT F(0) is to be: Q F(a) = 20 sinc(10 -+sinc(10a+5 B. F(@) = 20( sinc(Sa-2)+ sinc(Sa + 2)) C. F(m) = 20( sinc(Se-/2)+sinc(sinc(Sa +/2) rect($t -5+reci(St + 20 D. F(@) = - -10 -3 10

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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9. Given a signal f(t) as shown below, Its FT F(a) is to be: a, F(@) = 20 sinc(10-+sinc(10w + B. F(@) = 20( sinc(Sa» – 2) +sinc(Sas + 2) C. F() = 20( sinc(Se-/2) + sinc(sinc(Sa + /2)) 20 rect(St -5+ rect(St + D. F() = -10 O O
Transcribed Image Text:9. Given a signal f(t) as shown below, Its FT F(a) is to be: a, F(@) = 20 sinc(10-+sinc(10w + B. F(@) = 20( sinc(Sa» – 2) +sinc(Sas + 2) C. F() = 20( sinc(Se-/2) + sinc(sinc(Sa + /2)) 20 rect(St -5+ rect(St + D. F() = -10 O O
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