9. Construct a 95% confidence interval for the true proportion in the population for an attorney who found that in a sample of 200 lawyers, 25% of them use advertisement to make themselves known. 10. Experts discovered from a sample of 70 murders, that 7 murders were committed by women. Construct a confidence interval at alpha (α = 0.01) for the true proportion of murders committed by women in the population?
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9. Construct a 95% confidence interval for the true proportion in the population for an attorney who found that in a sample of 200 lawyers, 25% of them use advertisement to make themselves known.
10. Experts discovered from a sample of 70 murders, that 7 murders were committed by women. Construct a confidence interval at alpha (α = 0.01) for the true proportion of murders committed by women in the population?
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- In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places < p <Lexi of Arm End insurance ,was hired to estimate the proportion of patients that had paid their Bill's on time. She took a random sample of 100 such patients and found that 85 of them had paid their Bill's on time. Help her find 96% confidence interval for population proportion. 1. What is the X and is the "n" sample size? What is the point estimate for the population proportion? 2 Estimate the 96% confidence interval for the proportion of people that paid their bills on time . 3 What is the standard error for the population proportion ? 4 The margin of error for the population proportion, is 4%Suppose we know that a confidence interval for a population proportion is (0.105,0.355), with a sample proportion of p̂=0.23. What is the margin of error?
- Suppose a new treatment for a certain disease is given to a sample of 180 patients. The treatment was successful for 153of the patients. Assume that these patients are representative of the population of individuals who have this disease. Calculate a 98% confidence interval for the proportion successfully treated. (Round the answers to three decimal places.)10. Suppose we sample 300 UNI students and find the 27 regularly wear a watch. Find a 98% confidence interval for p, the percentage of all UNI students who regularly wear a watch.We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 34 had kids. Based on this, construct a 90% confidence interval for the proportion, p, of adult residents who are parents in this county. Give your answers as decimals, to three places.
- A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?13. In another pre-election poll, a pollster finds that 438 out of 600 people polled favor Smith. Construct the 95% confidence interval for the proportion (to nearest 0.001) of people in the whole population who favor Smith.In a sample of 300 adults, 198 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places RectanIn a sample of 360 adults, 266 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesIn a sample of 510 adults, 281 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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