Lexi of Arm End insurance ,was hired to estimate the proportion of patients that had paid their Bill's on time. She took a random sample of 100 such patients and found that 85 of them had paid their Bill's on time. Help her find 96% confidence interval for population proportion. 1. What is the X and is the "n" sample size? What is the point estimate for the population proportion? 2 Estimate the 96% confidence interval for the proportion of people that paid their bills on time . 3 What is the standard error for the population proportion ?
Lexi of Arm End insurance ,was hired to estimate the proportion of patients that had paid their Bill's on time. She took a random sample of 100 such patients and found that 85 of them had paid their Bill's on time. Help her find 96% confidence interval for population proportion.
1. What is the X and is the "n"
What is the point estimate for the population proportion?
2 Estimate the 96% confidence interval for the proportion of people that paid their bills on time .
3 What is the standard error for the population proportion ?
4 The margin of error for the population proportion, is 4%
Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a time so we are answering the first three as you have not mentioned which of these you are looking for. Please re-submit the question separately for the remaining sub-parts.
Given,
n = 100
x = 85
level of significance = 0.04
To find,
1) x=?, n = ?, p = ?
2) 96% confidence interval
3) standard error
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