9. Compound A, C;H12, is optically active. On catalytic reduction over a palladium catalyst, 2 equivalents of hydrogen are absorbed, yielding compound B, C-H16. Ozonolysis of A, produces two fragments. One is acetic acid, CH3COOH. The other fragment, C, is an optically active carboxylic acid, C4H9-COOH. Write the reactions and identify A, B, and C. 2H, C,H12 C,H16 Pd A В 1. O3 C,H12 CH,COOH optically active C,H,COOH 2. Zn, H* A
9. Compound A, C;H12, is optically active. On catalytic reduction over a palladium catalyst, 2 equivalents of hydrogen are absorbed, yielding compound B, C-H16. Ozonolysis of A, produces two fragments. One is acetic acid, CH3COOH. The other fragment, C, is an optically active carboxylic acid, C4H9-COOH. Write the reactions and identify A, B, and C. 2H, C,H12 C,H16 Pd A В 1. O3 C,H12 CH,COOH optically active C,H,COOH 2. Zn, H* A
Chemistry
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Chapter1: Chemical Foundations
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Epoxides are a special class of cyclic ethers which are an important functional group in organic chemistry and generate reactive centers due to their unusual high reactivity. Due to their high reactivity, epoxides are considered to be toxic and mutagenic.
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An organic reaction in which an organohalide and a deprotonated alcohol forms ether is known as Williamson ether synthesis. Alexander Williamson developed the Williamson ether synthesis in 1850. The formation of ether in this synthesis is an SN2 reaction.
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![**Chemical Reaction Analysis**
**Problem Statement:**
Compound A, C₇H₁₂, is optically active. Upon catalytic reduction over a palladium catalyst, 2 equivalents of hydrogen are absorbed, resulting in compound B, C₇H₁₆. Ozonolysis of A yields two fragments. One is acetic acid, CH₃COOH. The other fragment, C, is an optically active carboxylic acid, C₄H₉COOH. Identify compounds A, B, and C by writing the reactions.
**Reactions:**
1. **Catalytic Hydrogenation Reaction:**
- **Starting Material (A):** C₇H₁₂
- **Catalyst:** Palladium (Pd)
- **Reagents:** 2 equivalents of H₂
- **Product (B):** C₇H₁₆
The reaction proceeds as:
\[
\text{C}_7\text{H}_{12} + 2\text{H}_2 \xrightarrow{\text{Pd}} \text{C}_7\text{H}_{16}
\]
2. **Ozonolysis Reaction:**
- **Starting Material (A):** C₇H₁₂
- **Reagents:**
1. Ozone (O₃)
2. Zinc (Zn), in acidic conditions (H⁺)
- **Products:**
- Acetic Acid: CH₃COOH
- Optically active carboxylic acid (C): C₄H₉COOH
The reaction proceeds as:
\[
\text{C}_7\text{H}_{12} \xrightarrow{\text{O}_3/ \text{Zn, H}^+} \text{CH}_3\text{COOH} + \text{optically active C}_4\text{H}_9\text{COOH}
\]
**Identity of Compounds:**
- **A (C₇H₁₂):** The original optically active compound
- **B (C₇H₁₆):** Resulting compound from hydrogenation
- **C (C₄H₉COOH):** Optically active carboxylic acid formed](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdaac3699-bbcf-491f-ae47-6900b381c75d%2Ff7cf871c-97ef-4331-a7e8-7bece7267b5b%2Ftqusrb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Chemical Reaction Analysis**
**Problem Statement:**
Compound A, C₇H₁₂, is optically active. Upon catalytic reduction over a palladium catalyst, 2 equivalents of hydrogen are absorbed, resulting in compound B, C₇H₁₆. Ozonolysis of A yields two fragments. One is acetic acid, CH₃COOH. The other fragment, C, is an optically active carboxylic acid, C₄H₉COOH. Identify compounds A, B, and C by writing the reactions.
**Reactions:**
1. **Catalytic Hydrogenation Reaction:**
- **Starting Material (A):** C₇H₁₂
- **Catalyst:** Palladium (Pd)
- **Reagents:** 2 equivalents of H₂
- **Product (B):** C₇H₁₆
The reaction proceeds as:
\[
\text{C}_7\text{H}_{12} + 2\text{H}_2 \xrightarrow{\text{Pd}} \text{C}_7\text{H}_{16}
\]
2. **Ozonolysis Reaction:**
- **Starting Material (A):** C₇H₁₂
- **Reagents:**
1. Ozone (O₃)
2. Zinc (Zn), in acidic conditions (H⁺)
- **Products:**
- Acetic Acid: CH₃COOH
- Optically active carboxylic acid (C): C₄H₉COOH
The reaction proceeds as:
\[
\text{C}_7\text{H}_{12} \xrightarrow{\text{O}_3/ \text{Zn, H}^+} \text{CH}_3\text{COOH} + \text{optically active C}_4\text{H}_9\text{COOH}
\]
**Identity of Compounds:**
- **A (C₇H₁₂):** The original optically active compound
- **B (C₇H₁₆):** Resulting compound from hydrogenation
- **C (C₄H₉COOH):** Optically active carboxylic acid formed
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