9. Assume that the content of 15-litres container is normally distributed.To test Ho: u = 15.2 against H1 : u > 15.2, we take a random sample of size n = 25 andobserve that i = 15.6 litres and s = 0.5 litre. (Use 0.01 level of significance)a) Perform the testing by using test statistic.b) Perform the testing by using p-value test.

GivenThe null and alternative hypothesis isH0:μ=15.2H1:μ>15.2sample…

Answered: 9. Assume that the content of 15-litres…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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a rescarch study reports tCH)=2.n. How many in the study? CHOW big was the sample? Is this E'statistic sufticrent to reject the nvil hypathos using a twotaiked test with a .oS? individuals participated
iven ˆpp^ = 0.2857 and N = 35 for the high income group,Test the claim that the proportion of children in the high income group that drew the nickel too large is smaller than 50%. Test at the 0.1 significance level.a) Identify the correct alternative hypothesis: p>.50p>.50 p<.50p<.50 μ=.50μ=.50 p=.50p=.50 μ<.50μ<.50 μ>.50μ>.50 Give all answers correct to 3 decimal places.b) The test statistic value is: c) Using the P-value method, the P-value is: d) Based on this, we Reject H0H0 Fail to reject H0
b) i. Let Y be the mean of sample of size n from a normal distribution with mean μ and variance 100. Find n so that Pu-5<Ỹ < µ+5)= 0.954
17. please state all 6 steps of the p method clearly please! Strength of concrete: The compressive strength, in kilopascals, was measured for concrete blocks from five different batches of concrete, both three and six days after pouring. The data are as follows. Can you conclude that the mean strength after three days differs from the mean strength after six days? Let μ1 represent the mean strength after three days and =μd−μ1μ2 . Use the =α0.05 level and the P -value method with the TI-84 Plus calculator. Block 1 2 3 4 5 After 3 days 1371 1379 1344 1383 1386 After 6 days 1328 1337 1344 1321 1345
9. Assume that the content of 15-litres container is normally distributed. To test Ho: µ = 15.2 against H, : µ> 15.2, we take a random sample of size n = 25 and observe that = 15.6 litres and s = 0.5 litre. (Use 0.01 level of significance) a) Perform the testing by using test statistic.
We collected a sample of twenty-five observations. We assumed that the observations are from a population whose values follow a normal distribution with a mean of u and a standard deviation of five. We performed a test with these hypotheses Ho: μ = 0H₁ = 0 and H₁ : μ0H₁0. The test statistic is the sample mean . The 5% rejection region is 1.959964 > 1.959964. What is the power of this test when μ = -2μ = -2? Please state the statistical power up to the fourth decimal place.
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Dasani has two machines at a particular plant that are used for filling their plastic water bottles (nominal volume 16 ounces). The quality engineering department tells the plant manager that both machines fill to the same net volume (whether or not this volume averages 16.0 ounces). A random sample is taken from the output of the each machine. Table 1-Measured volume of water per bottle (fluid ounces) Machine 1 Machine 2 16.03 16.01 16.02 16.03 16.04 15.96 15.97 16.04 16.05 15.98 15.96 16.02 16.05 16.02 16.01 16.01 16.02 15.99 15.99 16.00 Do you think the quality engineering department is correct? Derive your answer from a complete hypothesis testing process.
PLS HELP!
Quality control at a soda bottler suspects that the variance in the mean volume of bottles of soda being filled by the bottler is intolerably high. In a sample of 14 bottles, the sample variance is 1.5 ml. Use this sample to test Ho: o? = 1.2 against H:0? > 1.2 at a = 0.05. a) Find the critical value or values for this test. b) Find the value of the test statistic. c) Give your decision in terms of the null hypothesis.
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A producer (spinner) supplies yarn of nominal linear density equal to be 45 tex. The customer (knitter) accepts yarn if its mean linear density lies within a range of 45±1.5 tex. As the knitter cannot test all the yarns supplied by the spinner, the knitter would like to devise an acceptance sampling scheme with 10% producer's risk and 5% consumer's risk. Assume the standard deviation of count within a delivery is 1.2 tex.

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