8. Let x be a random variable that represents micrograms of lead per liter of water(ug/L). An Industrial plant discharges water into a creek. The EnvironmentalProtection Agency has studied the discharged water and found x to have a normaldistribution, with a-0.7 (ug/L (Reference: EPA Wetlands Case Studies).The industrial plant says that the population mean value of x Is u-2.0 mg/L However,a random sample of n-10 water samples showed that -2.56 mg/L Consider theclalm that lead-concentration population mean is higher than the industrial plantclaims? Suppose a =1%.a. Find the P-value.b. Find the critical value zo that defines the rejection region.c Would you support the claim? Why?d. Find a 95% confidence interval for u.e. How large a sample should be taken to be 95% confident that the sample mean x iswithin a margin of error E-0.2mg/L of the population mean?

We have given that the hypothetical mean mu=2, sample mean x-bar=2.56, standard deviation 0.7 and…

&. Let x be a random varlable that represents micrograms of lead per liter of water (ug/L). An Industrial plant discharges water into a creek. The Environmental Protection Agency has studied the discharged water and found x to havea normal distribution, with o -0.7 (ug/L (Reference EPA Wetlands Case Studies). The industrial plant says that the population mean value of x is u-2.0 mg/L However, a random sample of n-10 water samples showed that X-2.56 mg/L Consider the claim that lead-concentration population mean is higher than the industrial plant claims? Suppose a =1%. a. Find the P-value. b. Find the critical value zo that defines the rejection region. c. Would you support the claim? Why? d. Find a 95% confidence inteng

&. Let x be a random varlable that represents micrograms of lead per liter of water (ug/L). An Industrial plant discharges water into a creek. The Environmental Protection Agency has studied the discharged water and found x to havea normal distribution, with o -0.7 (ug/L (Reference EPA Wetlands Case Studies). The industrial plant says that the population mean value of x is u-2.0 mg/L However, a random sample of n-10 water samples showed that X-2.56 mg/L Consider the claim that lead-concentration population mean is higher than the industrial plant claims? Suppose a =1%. a. Find the P-value. b. Find the critical value zo that defines the rejection region. c. Would you support the claim? Why? d. Find a 95% confidence inteng

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The boiling point of 16 samples of a certain brand of hydrogenated vegetable oil used in a fryer was collected, resulting in Xbar=152.1 degrees. Assume that the distribution of melting point is normal with o=3.20. If the boiling point is different than 150 degrees, then either the oil will be too hot and will burn food or it will be too cool and will not properly cook the food. Is the sample mean significantly different from the target of 150 degrees? Use alpha=0.01 Но: H1: Define critical (rejection) region(s): Calculate the appropriate test statistic: What decision do we make? What this decision means in terms of this problem?
The data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.025 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions? Click the icon to view the data. What are the hypotheses for this test? O A. Ho: At least one of the means is different from the others. H₁ H₁ H₂ H3 OB. Ho: H₁ H₁: H1 H₂ =H3 H₂ H3 OC. Ho: H₁ H₂ H3 H₁: At least one of the means is different from the others. O D. Ho: H₁ H₂ H3 H₁: H₁ H₂ =H3 Data Table Type A 6.2 6.2 6.5 7.4 7.1 6.1 6.9 7.3 6.9 6.7 Print C Type B 7.7 7.5 8.7 8.1 8.6 8.8 8.4 8.5 Type C 8.5 9.3 9.6 9.1 9.1 9.1 9.8 9.5 9.9 Done O X
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Low‑density lipoprotein, or LDL, is the main source of cholesterol buildup and blockage in the arteries. This is why LDL is known as "bad cholesterol." LDL is measured in milligrams per deciliter of blood, or mg/dL. In a population of adults at risk for cardiovascular problems, the distribution of LDL levels is normal, with a mean of 123123 mg/dL and a standard deviation of 4141 mg/dL. If an individual's LDL is at least 11 standard deviation or more above the mean, he or she will be monitored carefully by a doctor. What percentage of individuals from this population will have LDL levels 11 or more standard deviations above the mean? Use the 6868–9595–99.799.7 rule. (Enter your exact answer as a whole number.)
A study is conducted to determine factors in solving missing persons cases. The outcome is Y; which is equal to 1 if the i-th missing person case is unsolved and 0 if it is solved. Let covariate X1; be an indicator equal to 1 if the i-th case is female and 0 for male. Let X2i be a categorical covariate of age group for the i-th case. Categories are less than 14 years old (base level/group), between 14 and 19 years old, and older than 19 years. Set u = P(Y = 1) and the following model is fit: logit(u) = Bo + BịI(Female) + B2I(14 to 19 yrs old) + B3I(> 19 yrs old) The output from the model is below: Estimate S.E. p-value Bo -4.565 0.128 0.380 0.087 B2 Вз -0.198 0.042 0.163 1.128 0.133 a. Using the logistic regression output, calculate the estimated odds ratio of a case being unsolved (again Y=1 is unsolved and Y=0 is solved) comparing females to males (female is the numerator odds) of the same age. Interpret this odds ratio in context of the problem. iii b. Create a 95% confidence…
lustration 19.33. An examination was given to 50 students at College A and to 60 students at Collage B. At A, the mean grade was 75 with S.D.=9. At B, the mean was 79 with SD=7. Is there a significant difference in the performance at the two Colleges at 5% level of significance?