9. A merry-go-round having a diameter of 12m rotates about its center at a rate of 5rpm. Determine the radial acceleration at the edge of the merry-go-round. Express your answer in ft/s^2. a. 6.54 ft/s^2 b. 3.29 ft/s^2 c. 1.64 ft/s^2 d. 5.40 ft/s^2
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- # 16. The frequency of a merry go round is 5 times per minute. What is the tangential velocity of the merry go round if it has a radius of 20.0 meters? a. 3.00 m/s b. .050 m/s c. 10.5 m/s d. 6.28 m/s #17. The frequency of a merry go round is 5 times per minute, and it has a radius of 20.0 meters. What is the angular velocity of the merry go round in degrees per second? a. 18.0 degrees/s b. .050 degrees/s c. 30.0 degrees/s d. 60.0 degrees/s1. Refer to figure 1. A spherical shell and solid sphere roll down a ramp with a 30.0° inclination. Calculate the final velocities of each sphere when they reach the bottom and the velocity of each sphere ½ the distance above the ground. 20.0m Solid sphere, about diameter Spherical shell, about diameter R MR² MR²Help with 15. Thank you.
- Q 3 please2. A particle moves in uniform circular motion, over a horizontal xy- plane. At one instant it moves through the points (2.0 m, 4.0 m) with a velocity of -6.00i m/s and an acceleration of 18.0j m/s?. a) Draw the circular path of the particle and label the velocity vector and the acceleration vector. b) Calculate the x and y-coordinates of the center of the circular path. c) Calculate the period of rotation.A circular disk of radius 0.010 m rotates at a rate of 5.0 rev/s. What is the acceleration of a point on the edge of the disk? a. 0.31 m/s2 b. 1.6 m/s2 c. 9.9 m/s2 d. 2500 m/s2 e. zero m/s2
- 4. Harnessing wind power has become an effective alternative to finding and refining fossil fuels. These wind turbines are now found all over Ontario. One of these turbines has a blade with an 8 metre diameter. The maximum height from the ground to the tip of the blade is 26 m. At an average wind speed, the blade makes 20 rotations every minute. Assuming that the tip of the blade starts at the lowest point, determine an equation for the height versus time.A 2kg toy is moving in a circle of radius 2.5 m with a speed of 3m/s.Calculate the centripetal acceleration of the toy? choose one correct answer with the correct units. A. 3.6 m/s^2 B. 1.2 m/s^2 C. 3.6 m/s D. 0.833 m/s^210. You're out in space, on a rotating wheel-shaped space station of radius 551 m. You feel planted firmly on the floor , due to artificial gravity. The gravity you experience is Earth-normal, that is, g = 9.81 m/s^2. How fast is the space station rotating in order to produce this much artificial gravity? Express your answer in revolutions per minute (rpm). 1.019 rpm 1.274 rpm 0.133 rpm 73.5 rpm
- - 4.0j A particle goes through uniform circular motion. At one instant, it is at the xy coordinates (-2.0 m, 3.0 m), has velocity = m/s, and has acceleration = 2.01 m/s². What is the x coordinate (m) of the center of the circle? O 06 O 11 04 O-5 O-6 08 004. Given the acceleration as a function of the angle theta, a = 6.5 sin θ + 2.3cos θ i. Find the optimal angle, so the acceleration is maximum. ii. Find the value of the maximum acceleration.Q 2 please