.5ks Froblem 3: A 50 gram ball tied to a 2 meter string is being swung in a circle. It takes 0.5 seconds for the ball to make one revolution. Irev 0.5. 2rpm A.4 EWhat is the centripetal acceleration of the ball? 60 min ac=(.5)?/2 rgm 2 rpm -3 -. 25/2rpm B. If the ball is being kept in a circular path by the string, then what is the tension in the string? - 5

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Name:
.5ks
Problem 3: A 50 gram ball tied to a 2 meter string is being swung in a circle. It takes 0.5 seconds
for the ball to make one revolution.
A.S What is the centripetal acceleration of the ball?
0.5.
Trev
2rpm
C60min
ac=(.5)?/2 rom
=.25/2rpm
- 125m/;2
B. If the ball is being kept in a circular path by the string, then what is the tension
in the string?
strins
2m
.125 mls
= ,0 0125m
Transcribed Image Text:Name: .5ks Problem 3: A 50 gram ball tied to a 2 meter string is being swung in a circle. It takes 0.5 seconds for the ball to make one revolution. A.S What is the centripetal acceleration of the ball? 0.5. Trev 2rpm C60min ac=(.5)?/2 rom =.25/2rpm - 125m/;2 B. If the ball is being kept in a circular path by the string, then what is the tension in the string? strins 2m .125 mls = ,0 0125m
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