A particle goes through uniform circular motion. At one instant, it is at the xy coordinates (-2.0 m, 3.0 m), has velocity = - 4.0j m/s, and has acceleration = 2.0 m/s. What is the x coordinate (m) of the center of the circle? 00000 N 06 O 11 04 0-5 3 0-6 08 00
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A particle goes through uniform circular motion. At one instant, it is at the xy coordinates (-2.0 m, 3.0 m), has velocity =
m/s, and has acceleration = 2.01 m/s². What is the x coordinate (m) of the center of the circle?
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06
O 11
04
O-5
O-6
08
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- An object travels in a vertical circle of 1.43 m radius. When the object is traveling downward and is 28.0° from its lowest point, its total acceleration is a = (18.51 + 16.2ĵ) m/s². At this instant, determine the following. (Take the angle 28.0° clockwise from the axis of the circle that intersects the center and the lowest point. Assume that the +x axis is to the right and the +y axis is up along the page.) esc 7 (a) magnitude of the radial acceleration m/s² (b) magnitude of the tangential acceleration m/s² (c) speed of the object m/s (d) velocity of the object (Express your answer in vector form.) m/s v= 1 ² F1 Q A 1 N 2 Q F2 W S 3 X # H option command 80 F3 E D $ 4 C 990 GOD F4 R F % 67 8 5 F5 V T MacBook Air 6 G F6 Y B & 7 H 4 F7 U N 00 * 8 J FB 1 ( 9 M F9 K O O < A I -10 L || ! P V F11 1 + { [ 2 412 1 - option commandA small object moves at constant speed in a horizontal circle of radius 0.540 m. If the object makes two complete revolutions in one second, what is the magnitude of the acceleration of the object?The figure shows thes initial position i and the final position f of a particle. 4 m, 3 m Part 1 3 m 4 m 3 m 4m 3 m 5 m 2 m/ What is the initial position vector in unit-vector notation? 2 m/ Ky 1 m n 5 m 1 m 3 m x 3 m x m î+ i m Ĵ+ i mk
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