(9 blanks) Derive the work done of an ideal gas undergoing isothermal expansion at temperature T1 if the volume changes from V1 to V2. Express in terms of P1 and P2. V2 W = Where: p= T/V By substitution: V2 dv W = vi V Applying the rules of integration, the word done will become Using: P1V1 = nRT & P2V2 = nRT The work done in terms of pressure is expressed as In W =
(9 blanks) Derive the work done of an ideal gas undergoing isothermal expansion at temperature T1 if the volume changes from V1 to V2. Express in terms of P1 and P2. V2 W = Where: p= T/V By substitution: V2 dv W = vi V Applying the rules of integration, the word done will become Using: P1V1 = nRT & P2V2 = nRT The work done in terms of pressure is expressed as In W =
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![QUESTION 2
(9 blanks) Derive the work done of an ideal gas undergoing isothermal expansion at temperature T1 if the volume changes from V1 to V2. Express in terms of P1 and P2.
V2
W =
Where: p=
T/V
By substitution:
.V2
dv
W =
V
Applying the rules of integration, the word done will become
W=
Using:
P1V1 = nRT & P2V2 = nRT
The work done in terms of pressure is expressed as
W =
In](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8fe46197-81df-4845-bab2-708c01ff8fda%2F0ec1133d-884c-4b7d-abc7-e2211c943729%2Fagapcm8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 2
(9 blanks) Derive the work done of an ideal gas undergoing isothermal expansion at temperature T1 if the volume changes from V1 to V2. Express in terms of P1 and P2.
V2
W =
Where: p=
T/V
By substitution:
.V2
dv
W =
V
Applying the rules of integration, the word done will become
W=
Using:
P1V1 = nRT & P2V2 = nRT
The work done in terms of pressure is expressed as
W =
In
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