A gas with initial state variables p₁, V₁, and T₁ is cooled in an isochoric process until p2 = P₁- Part A By what factor does the volume change? Submit ▾ Part B [Γ] ΑΣΦ Submit Request Answer By what factor does the temperature change? [5] ΑΣΦ Request Answer ?

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**Description:**

The image presents an educational activity involving a thermodynamics problem related to an isochoric process. It consists of descriptive text and two interactive parts labeled Part A and Part B.

**Text Explanation:**

A gas with initial state variables \( p_1, V_1, \) and \( T_1 \) is cooled in an isochoric process until \( p_2 = \frac{1}{3} p_1 \).

**Part A:**

- **Question:** By what factor does the volume change?
- **Interactive Equation Input:** \( \frac{V_2}{V_1} = \) 
  - An input field is provided to enter the factor of volume change.
  - Features include a calculator, reset options, and a button to submit the answer with an option to request the answer if needed.

**Part B:**

- **Question:** By what factor does the temperature change?
- **Interactive Equation Input:** \( \frac{T_2}{T_1} = \)
  - An input field is provided to enter the factor of temperature change.
  - Similar interactive options as Part A are available for user interaction and answer submission.

**Explanation of the Process:**

- **Isochoric Process:** This refers to a thermodynamic process wherein the volume remains constant. Since the process is isochoric, the volume change \( \frac{V_2}{V_1} \) should theoretically be 1.
- **Pressure and Temperature Relationship:** According to Gay-Lussac's law, in an isochoric process, the pressure and temperature of a gas are directly proportional. Hence, the temperature will change in the same ratio as the change in pressure. Therefore, the factor for temperature change \( \frac{T_2}{T_1} \) is equivalent to \( \frac{1}{3} \).

This educational exercise helps students understand the behavior of gases under specific conditions and reinforces the principles of isochoric processes.
Transcribed Image Text:**Description:** The image presents an educational activity involving a thermodynamics problem related to an isochoric process. It consists of descriptive text and two interactive parts labeled Part A and Part B. **Text Explanation:** A gas with initial state variables \( p_1, V_1, \) and \( T_1 \) is cooled in an isochoric process until \( p_2 = \frac{1}{3} p_1 \). **Part A:** - **Question:** By what factor does the volume change? - **Interactive Equation Input:** \( \frac{V_2}{V_1} = \) - An input field is provided to enter the factor of volume change. - Features include a calculator, reset options, and a button to submit the answer with an option to request the answer if needed. **Part B:** - **Question:** By what factor does the temperature change? - **Interactive Equation Input:** \( \frac{T_2}{T_1} = \) - An input field is provided to enter the factor of temperature change. - Similar interactive options as Part A are available for user interaction and answer submission. **Explanation of the Process:** - **Isochoric Process:** This refers to a thermodynamic process wherein the volume remains constant. Since the process is isochoric, the volume change \( \frac{V_2}{V_1} \) should theoretically be 1. - **Pressure and Temperature Relationship:** According to Gay-Lussac's law, in an isochoric process, the pressure and temperature of a gas are directly proportional. Hence, the temperature will change in the same ratio as the change in pressure. Therefore, the factor for temperature change \( \frac{T_2}{T_1} \) is equivalent to \( \frac{1}{3} \). This educational exercise helps students understand the behavior of gases under specific conditions and reinforces the principles of isochoric processes.
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