82. Match the statements of Column I with values of Column II. Column I Column II (A) If f(x) x +1 when x <0 = x-1 for x 20, then (p) fof (x) for -1 s x < 0 is x -3 2 tan x (cos 2x + 1)(sec x + 2 tan x) (B) If f (q) x + 2x 1 + tan? x then f(x) is (C) If f(x + y + 1) = (/f(x) + JF(y)² for all x, y e Rand f(0) = 1, then f(x) is (r) 1+* %3D (D) If 4< x < 5 and f(x) + 2x + 2 where [yl is the (s) (r+ 1) greatest integer < y, then f(x) is
82. Match the statements of Column I with values of Column II. Column I Column II (A) If f(x) x +1 when x <0 = x-1 for x 20, then (p) fof (x) for -1 s x < 0 is x -3 2 tan x (cos 2x + 1)(sec x + 2 tan x) (B) If f (q) x + 2x 1 + tan? x then f(x) is (C) If f(x + y + 1) = (/f(x) + JF(y)² for all x, y e Rand f(0) = 1, then f(x) is (r) 1+* %3D (D) If 4< x < 5 and f(x) + 2x + 2 where [yl is the (s) (r+ 1) greatest integer < y, then f(x) is
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
match the following , do proper solution.
![82. Match the statements of Column I with values of Column II.
Column I
Column II
(A) If f(x)=x + 1 when x < 0 = x-1 for x20, then (p)
fof (x) for -1 s x < 0 is
x-3
2.
(B) If f
2 tan x
(cos 2x + 1)(sec" x + 2 tan x)
(q) x + 2x
%3D
1 + tan x
2
then f(x) is
(C) If f(x + y + 1) = (/f(x) + Jf (y)²
for all x, y e R and f(0) 1, then f(x) is
(r) 1 +x
(D) If 4 < x < 5 and f(x)
+ 2x + 2 where [y] is the (s) (r+ 1)
greatest integer <y, then f(x) is](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa72b4f97-71ac-443e-b8dd-0599cf310438%2F7fc651ef-a6d9-4200-81bc-f34accb02ed9%2Fxy9l8h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:82. Match the statements of Column I with values of Column II.
Column I
Column II
(A) If f(x)=x + 1 when x < 0 = x-1 for x20, then (p)
fof (x) for -1 s x < 0 is
x-3
2.
(B) If f
2 tan x
(cos 2x + 1)(sec" x + 2 tan x)
(q) x + 2x
%3D
1 + tan x
2
then f(x) is
(C) If f(x + y + 1) = (/f(x) + Jf (y)²
for all x, y e R and f(0) 1, then f(x) is
(r) 1 +x
(D) If 4 < x < 5 and f(x)
+ 2x + 2 where [y] is the (s) (r+ 1)
greatest integer <y, then f(x) is
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