D. E. php $y = 10;
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Max Function
Statistical function is of many categories. One of them is a MAX function. The MAX function returns the largest value from the list of arguments passed to it. MAX function always ignores the empty cells when performing the calculation.
Power Function
A power function is a type of single-term function. Its definition states that it is a variable containing a base value raised to a constant value acting as an exponent. This variable may also have a coefficient. For instance, the area of a circle can be given as:
Please solve the parts, D, E and F
![D.<?php
function zzNew()
{ $g = 1;
F.
$q = $g + 6;
echo $q;
zzNew();
$g =
= 2;
echo $g;
?>
E. <?php
$y = 10;
function myTest()
{
$GLOBALS['y'] = $GLOBALS['y'] + 2;
}
myTest();
echo $y;
?>
<?php
define("z", 6);
function myTest2()
{ echo z; }
myTest2();
?>](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1f4b5cd7-f3c9-4bf3-b5b4-fe47004d1590%2Fc32c81f3-de10-469c-b374-21d0d1afb9c2%2Fhen7tvg_processed.jpeg&w=3840&q=75)
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- PROBLEM: Create a void function that prompts the user to input values for the following: • DC voltage source supply in volts; • two resistor values in ohms; and • the connection of the two resistors (whether parallel or series). The program will output the following: • total resistance depending on the selected connection in ohms; • total current in the circuit in amperes; • voltage across each resistor in volts; and • current through each resistor in amperes. SPECIFICATIONS: - You may only use the codes that we studied under our lectures - All lines of codes should have a comment. - Save your cpp file as Surname_FE (Example: Pangaliman_FE.cpp) TEST CASES: User inputs valid values User inputs character in parameter list Input: DC voltage source: 10 V DC voltage source: 10 R1: 100 R2: 200 R1: 100 ohms R2: 200 ohms Connection (1= series or 2 = parallel): 1 Output: Total resistance: 300 ohms Connection (1= series or 2 = parallel): 1 Invalid input! Total current: 0.0333 amperes V_R1: 3.33…PROBLEM: Create a void function that prompts the user to input values for the following: • DC voltage source supply in volts; • two resistor values in ohms; and • the connection of the two resistors (whether parallel or series). The program will output the following: • total resistance depending on the selected connection in ohms; • total current in the circuit in amperes; • voltage across each resistor in volts; and • current through each resistor in amperes. SPECIFICATIONS: - You may only use the codes that we studied under our lectures - All lines of codes should have a comment. - Save your cpp file as Surname_FE (Example: Pangaliman_FE.cpp) TEST CASES: User inputs valid values Input: DC voltage source: 10 R1: 100 R2: 200 Connection (1= series or 2 = parallel): 1 Output: Total resistance: 300 ohms Total current: 0.0333 amperes V_R1: 3.33 volts V_R2: 6.67 volts I_R1: 0.0333 amperes IR2: 0.0333 amperes User inputs a 0 resistance for series DC voltage source: 5 R1:0 R2: 10 Connection…A sphere is characterized by a single dimensions; its radius (r). The surface area of the sphere is calculated as A=4πr2 While the volume is calculated as V=43πr3 Write a program that asks the user for r and when VALID proceeds to calculate both the surface area and the volume of the sphere by calling a single function. The function's prototype is as follows: void sphereCalc(float, float *, float *); All console input and output operations are in main(). Print the area and volyme with 3 decimal places. Follow best programming practices. Use r = 3 for the screenshot. Hint: Define PI using #define PI 3.1415927
- JAVA CODE PLEASE Functions With No Parameters and Return Values Practice ll by CodeChum Admin Create a program that has a global integer variable assigned to a value of 1. Then, create a new function named increment that increments the global variable. In the main function, if the current value of the global variable is divisible by 3, print “Cody!”. Otherwise, print the value of that global variable. Repeatedly call the increment function until the value of the global variable is greater than 15. Output Multiple lines containing a string or an integer 1 2 Cody! 4 5 Cody! 7 8 Cody! 10 11 Cody! 13 14 Cody! Score:Lowest Score Drop Write a program that calculates the average of a group of test scores, where the lowest score in the group is dropped. It should use the following functions: void getScore() should ask the user for a test score, store it in a reference parameter variable, and validate it. This function should be called by main once for each of the five scores to be entered. void calcAverage() should calculate and display the average of the four highest scores. This function should be called just once by main and should be passed the five scores. int findLowest() should find and return the lowest of the five scores passed to it. It should be called by calcAverage, which uses the function to determine which of the five scores to drop. Input Validation: Do not accept test scores lower than 0 or higher than 100.#include <stdio.h>void cubeByReference( int *nPtr ); // function prototypeint main( void ){ int number = 5; // initialize number printf("The original value of number is %d", number ); // pass address of number to cubeByReference cubeByReference( &number ); printf("\nThe new value of number is %d\n", number );} // end main void cubeByReference( int *nPtr ){ *nPtr = *nPtr* *nPtr* *nPtr;} passing argument by reference - We modify the code above 1- define a second argument (example "int number2 = 9") and a pointer to it 2- define a second function (addByReference) that adds number2 to number - passing both arguments by reference 3- print-out the result (that is in number) Upload the output and .c code
- The following function has errors. Locate as many errors as you can. void getValue(int value&) { cout << "Enter a value: "; cin >> value&;}What value does function Joy return when called with a value of 4?int Joy (int Q){ if (Q <= 1) return 1; else return Q * Joy(Q-1);}Mark the following statements as true or false: a. To use a predefined function in a program, you need to know only the name of the function and how to use it. (1) b. A value-returning function returns only one value. (2, 3) c. Parameters allow you to use different values each time the function is called. (2, 7, 9) d. When a return statement executes in a user-defined function, the function immediately exits. (3, 4) e. A value-returning function returns only integer values. (4) f. A variable name cannot be passed to a value parameter. (3, 6) g. If a C++ function does not use parameters, parentheses around the empty parameter list are still required. (2, 3, 6) h. In C + + , the names of the corresponding formal and actual parameters must be the same. (3, 4, 6) i. A function that changes the value of a reference parameter also changes the value of the actual parameter. (7) j. Whenever the value of a reference parameter changes, the value of the actual parameter changes. (7) k. In C++, function definitions can be nested; that is, the definition of one function can be enclosed in the body of another function. (9) l. Using global variables in a program is a better programming style than using local variables, because extra variables can be avoided. (10) m. In a program, global constants are as dangerous as global variables. (10) n. The memory for a static variable remains allocated between function calls. (11)
- (Civil eng.) Write an assignment statement to calculate the linear expansion in a steel beam as a function of temperature increase. The formula for linear expansion, l, is as follows: l=l0(1+(TfT0)) l0isthelengthofthebeamattemperatureT0.isthecoefficientoflinearexpansion.Tfisthefinaltemperatureofthebeam.#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05);cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05); cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…
