8.2 (A). Calculate the dimensions of a hollow steel shaft which is required to transmit 750 kW at a speed of 400 rev/min if the maximum torque exceeds the mean by 20% and the greatest intensity of shear stress is limited to 75 MN/m2. The internal diameter of the shaft is to be 80% of the external diameter. (The mean torque is that derived from the horsepower equation.) [135.2, 108.2 mm.]

Q: Power transmitted by a hollow shaft at 300 rpm is 800 kW. The ratio of outer diameter to the inner…

A: Given data:-         power=800Kw     N=300rpm dodi=1.5         Tmax=1.4   Tmean      τper=80 MPa…

Q: a steel shaft is 100 hp at a speed of 950 rpm. the shear stress is 8000 psi. what is the economical…

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Q: Problem 4

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Q: Determine the minimal value of a radius of the circular-solid shaft in problem 1 such that the…

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Q: Part A A steel tube having an outer diameter transmit 9 hp when turning at 27 rev/min. 1 hp = 550…

A: Given data:The outer diameter, do = 2.5 in.The power transmitted, P = 9 hp.The turning revolution, N…

Q: В x (in) r = 2e0.05x 100 kip-in r (in) A 10 in 100 kip-in The solid torsional shaft above is…

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Q: (2) The shaft consists of a 3-in diameter aluminum segment that is rigidly joined to a 2-in diameter…

A: Given data:Applied torque The diameter of the aluminiumThe diameter of the steelLength of the…

Q: (a) The tubular rotor shaft of a wind turbine shown in Figure 3(a) is of 50 mm and 40 mm outer and…

A: Given data Outer Diameter of Tubular shaft = Do = 50 mm = 0.05 mInner Diameter of Tubular Shaft = Di…

Q: A solid 1.6 in. diameter shaft is used to synchronize multiple mechanisms in a manufacturing plant.…

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Q: Select the size of a hollow steel shaft necessary to transmit 150 hp at 250 rpm without exceeding an…

A: Given data,    Power=150hp    speed=250 rpm    shear stress=4.7ksi    angle  of twist =0.35°…

Q: 8.14 (B). Calculate the minimum diameter of a solid shaft which is required to transmit 70 kW at 600…

A: According to the given data P=70kW N=600rpm τmax=75MN/m2=75 MPa We need to find  (a) Minimum…

Q: The bending stress at point A.

A: Given data Outer Diameter of Shaft = Do = 50 mm = 0.05 mInner Diameter of Shaft = Di = 40 mm = 0.04…

Q: The drive shaft AB of an automobile is made of a steel having an allowable shear stress of Tallow =…

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Q: A 3 ft long solid SAE4340 OQT1000 steel shaft is required to transmit a power of 200 HP. The shaft…

A: Given data as question Length of shaft = 3 feet Power of shaft = 200 hp Sped of shaft = 1500 rpm…

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.