8. What mass of sodium benzoate should you add to 150.0mL of a 0.15M benzoic acid solution to obtain a buffer with a pH of 4.25?

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**Question 8:**

What mass of sodium benzoate should you add to 1500 mL of a 0.15 M benzoic acid solution to obtain a buffer with a pH of 4.25?

---

This question involves preparing a buffer solution using sodium benzoate and benzoic acid. The challenge is to determine the appropriate mass of sodium benzoate needed to achieve the desired pH. 

To approach this problem, consider the Henderson-Hasselbalch equation:

\[ \text{pH} = \text{pKa} + \log \left( \frac{[\text{A}^-]}{[\text{HA}]} \right) \]

Where:
- [A⁻] is the concentration of the base form (sodium benzoate).
- [HA] is the concentration of the acid form (benzoic acid).

Given:
- Volume = 1500 mL (1.5 L)
- Initial concentration of benzoic acid, [HA] = 0.15 M
- Desired pH = 4.25

The goal is to solve for the mass of sodium benzoate needed. 

Note: The specific pKa value of benzoic acid is required to use the equation, typically around 4.2 for benzoic acid. Adjust calculations accordingly.
Transcribed Image Text:**Question 8:** What mass of sodium benzoate should you add to 1500 mL of a 0.15 M benzoic acid solution to obtain a buffer with a pH of 4.25? --- This question involves preparing a buffer solution using sodium benzoate and benzoic acid. The challenge is to determine the appropriate mass of sodium benzoate needed to achieve the desired pH. To approach this problem, consider the Henderson-Hasselbalch equation: \[ \text{pH} = \text{pKa} + \log \left( \frac{[\text{A}^-]}{[\text{HA}]} \right) \] Where: - [A⁻] is the concentration of the base form (sodium benzoate). - [HA] is the concentration of the acid form (benzoic acid). Given: - Volume = 1500 mL (1.5 L) - Initial concentration of benzoic acid, [HA] = 0.15 M - Desired pH = 4.25 The goal is to solve for the mass of sodium benzoate needed. Note: The specific pKa value of benzoic acid is required to use the equation, typically around 4.2 for benzoic acid. Adjust calculations accordingly.
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