8. a) Which of the following mixtures would result in a buffer solution? Very briefly explain whyfor each one.i.100 mL of 0.1M sodium acetate (NaOAc) + 50 mL of 0.1M hydrobromic acid(HBr).ii.50 mL of 0.01M acetic acid (HOAC) + 150 mL of 0.01M sodium hydroxide (NaOH).iii.100 mL of 0.02M sodium fluoride (NaF) + 50 mL of 0.02M potassium hydroxide(КОН).8. b) Calculate the pH of a buffer that was prepared by mixing 45 mL of 0.01M aqueoushydrocyanic acid (HCN, Ka = 6.2 x 10-10) with 11 mL of 0.02M aqueous potassiumhydroxide (KOH).

Since you have posted multiple unrelated questions, we are entitled to answer the first only. a) To…

Which of the following mixtures would result in a buffer solution? Very briefly explain why for each one. i. 100 mL of 0.1M sodium acetate (NaOAc) + 50 mL of 0.1M hydrobromic acid (HBr). ii. 50 mL of 0.01M acetic acid (HOAC) + 150 mL of 0.01M sodium hydroxide (NaOH). 100 mL of 0.02M sodium fluoride (NaF) + 50 mL of 0.02M potassium hydroxide (КОН). ii.

Which of the following mixtures would result in a buffer solution? Very briefly explain why for each one. i. 100 mL of 0.1M sodium acetate (NaOAc) + 50 mL of 0.1M hydrobromic acid (HBr). ii. 50 mL of 0.01M acetic acid (HOAC) + 150 mL of 0.01M sodium hydroxide (NaOH). 100 mL of 0.02M sodium fluoride (NaF) + 50 mL of 0.02M potassium hydroxide (КОН). ii.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Can you help me with #2
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Which of the following mixtures would result in a buffer solution when 1.0 L of the two solutions are mixed? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 0.2 M HNO3 and 0.4 M NaNO3 b 0.2 M HNO3 and 0.4 M HF 0.2 M HNO3 and 0.4 M NaF d. 0.2 M HNO3 and 0.4 M NaOH e None of the above would result in a buffer solution.
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Could you explain how to do this with great detail?
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