8. Two independent random variables X1=(-1.0.1) and X2-(0.1) can take the following probability values: P(X1=-1)=p, P(X1=0)=p/2, P(X_1=1) 1-3p/2, P(X_2=0)=p. P(X 2=1)=1-D. If Y-X1 X2, determine the average E(Y).
8. Two independent random variables X1=(-1.0.1) and X2-(0.1) can take the following probability values: P(X1=-1)=p, P(X1=0)=p/2, P(X_1=1) 1-3p/2, P(X_2=0)=p. P(X 2=1)=1-D. If Y-X1 X2, determine the average E(Y).
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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
Transcribed Image Text:8. Two independent random variables X1=(-1.0.1) and X2-(0.1) can take the following
probability values:
P(X1=-1)=p,
P(X1=0)=p/2,
P(X 1=1) 1-3p/2,
P(X_2=0)=p,
PIX 2=1)=1-D.
If Y-X1 X2, determine the average E(Y).
E(Y) =?
X₁ = (-1,0, 1) y X₂ = (0, 1)
P(X₁ = -1) = p
P(X₁ = 0) = {
P(X₁ = 1) = 1 -
T
P(X₂ = 0) = p
P(X₂= 1) = 1-p
Y = X₁ + X₂
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