2. Suppose that Y is a binomial random variable based on n trials with success probability p and consider Y*=n-Y. a Argue that for y* = 0, 1,..., n P(Y* = y*) = P(n − Y = y*) = P(Y = n − y*). b Use the result from part (a) to show that n P(Y* = y*) = = (₁ " y₁) p^-' q²" = (".)q" p²-x. n-y* c The result in part (b) implies that Y* has a binomial distribution based on n trials and "success" probability p* = q = 1 - p. Why is this result "obvious"?
2. Suppose that Y is a binomial random variable based on n trials with success probability p and consider Y*=n-Y. a Argue that for y* = 0, 1,..., n P(Y* = y*) = P(n − Y = y*) = P(Y = n − y*). b Use the result from part (a) to show that n P(Y* = y*) = = (₁ " y₁) p^-' q²" = (".)q" p²-x. n-y* c The result in part (b) implies that Y* has a binomial distribution based on n trials and "success" probability p* = q = 1 - p. Why is this result "obvious"?
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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