8. The following sample of 16 measurements was selected from a population that is approximatelynormally distributed.61 85 92 77 83 81 75 7895 S7 69 74 76 84 80 83Construct a 90% confidence interval for the population mean.

Since the sample size is small and population standard deviation is unknown, t distribution can be…

Answered: 8. The following sample of 16…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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5. Listed below are the values (in dollars) that a random sample of Americans spent on fast food per month. a. Construct a 99% confidence interval of the mean value of money spent on fast food by all Americans. 100 156 67 41 78 62 112 120 70 42 89 85 96 97 11 56 100 98 80 98 20 64 101 100 15 71 35 72 121 74 b. Interpret these results with respect to the amount Americans spend on fast food.
Consider the following random sample from a normal population: 14, 10, 13, 16, 12, 18, 15, and 11. WWhat is the 95% confidence interval for the population variance? O A. 6.54 to 38.82 O B. 1.12 to 5.69 O C. 11.39 to 15.86 O D. 3.11 to 29.51
Create a 95% confidence interval for the data set below. 70 59 58 72 66 58 70 70 64 59 56 68 72 68 ( , ) [three decimal accuracy] [three decimal accuracy]
Assume that samples have been randomly selected from normally distributed populations.The table below shows the weights of 9 subjects before and after following a particular diet for two months. Subject A B C D E F G H I Before 169 180 157 133 202 124 190 210 181 After 162 178 145 125 181 126 182 195 163 Construct a 99% confidence interval for the mean difference of the "before" minus "after" weights. Interpret the results.
Answer A B C
Consider the following random sample from a normal population given in the tablebelow. What is the 95% confidence interval for the population variance? 14 10 13 16 12 18 15 1115 17 19 14 12 13 17 16
9. A random sample of 25 statistics examinations was taken. The average score in the sample was 76 with a variance of 144. Assuming the scores are normally distributed, the 99% confidence interval for the population average examination score is a. 70.02 to 81.98 b. 69.82 to 82.18 C. 70.06 to 81.94 d. 69.48 to 82.52
2) The following data represent the number of passengers per flight in a random sample of 20 flights from Vienna, Austria, to Cluj-Napoca, Romania, with a new airline: 96 95 70 74 28 63 64 94 37 83 25 48 80 52 48 52 38 47 79 65 a) Find a 99% confidence interval for the mean number of passengers per flight. b) Find a 95% confidence interval for the population standard deviation.
(10%) The following medians were obtained from random samples 11 10 13 9. 7 13 11 12 8 10 9 9. 15 7 14 16 7 12 10 12 8 9 15 10 12 6. 7 Do the data support the belief that the median is less than 10? Use a = .05
The data set below represents the weights in grams of 10 randomly selected adult male fox squirrels from a forest. Assume the weights are normally distributed. 821 857 782 930 720 821 794 876 810 840 Find the sample mean and sample standard deviation Construct a 90% confidence interval for the population mean. Interpret the results from b.
Given below are the sodium contents in milligrams for seven brands of hot dogs rated as “very good” by Consumer Reports. Find a 99.9% confidence interval for the true mean amount of sodium for “very good” hotdogs. 400 470 350 365 270 550 530
Given two dependent random samples with the following results: Population 1 48 29 32 29 38 31 28 Population 2 45 38 41 16 40 28 38 Use this data to find the 95% confidence interval for the true difference between the population means. Assume that both populations are normally distributed. Copy Data Step 2 of 4 : Calculate the sample standard deviation of the paired differences. Round your answer to six decimal places.

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8. The following sample of 16 measurements was selected from a population that is approximately normally distributed. 61 85 92 77 83 81 75 78 95 S7 69 74 76 84 80 83 Construct a 90% confidence interval for the population mean.