2) The following data represent the number of passengers per flight in a random sample of 20flights from Vienna, Austria, to Cluj-Napoca, Romania, with a new airline:9695707428636494378325488052485238477965a) Find a 99% confidence interval for the mean number of passengers per flight.b) Find a 95% confidence interval for the population standard deviation.

Confidence Interval: In statistics, we can say a range of values of the specified population…

2) The following data represent the number of passengers per flight in a random sample of 20 flights from Vienna, Austria, to Cluj-Napoca, Romania, with a new airline: 83 70 96 74 28 63 64 94 37 95 48 80 52 48 52 38 47 79 65 25 a) Find a 99% confidence interval for the mean number of passengers per flight. b) Find a 95% confidence interval for the population standard deviation.

2) The following data represent the number of passengers per flight in a random sample of 20 flights from Vienna, Austria, to Cluj-Napoca, Romania, with a new airline: 83 70 96 74 28 63 64 94 37 95 48 80 52 48 52 38 47 79 65 25 a) Find a 99% confidence interval for the mean number of passengers per flight. b) Find a 95% confidence interval for the population standard deviation.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

The following sample of 16 measurements was selected from a population that is approximately normally distributed.Construct a 90% confidence interval for the population mean.
Fifteen randomly selected college students were asked to state the number of hours they slept the night before. The resulting data are: 6 16 7 8 7 796 3 11 9 15 4 7 9 a) Find the mean. b) Find the median. c) Find the standard deviation. d) According to Chebysev's Theorem, at least 75% of the times will fall between what two amounts? Is the theorem accurate for this set of data? Why of Why not? e) Are any of the reported hours "unusually" high? Are any of the reported hours unusually low?
2. University researchers claim that the average enrollment at four-year colleges is higher than two-year community colleges. Two surveys are undertaken at 35 four-year universities and 35 two-year colleges. The mean enrollment at the four-year institutions was 5,466 with a standard deviation of 8,191. The average enrollment at the two-year schools was 5,068 with a standard deviation of 4,777. Using a 95% confidence level, are the findings of the surveys consistent with the university researchers’ claim? 2. Does the null hypothesis reject H0 or fail to reject H0?
4. on paper. random sample of 130 human body temperatures had a mean 98.25 degree and astandard deviation of 0.73 degree. Construct a 99% confidence interval for the average body temperature ofhealthy people.
Given below are the sodium contents in milligrams for seven brands of hot dogs rated as “very good” by Consumer Reports. Find a 99.9% confidence interval for the true mean amount of sodium for “very good” hotdogs. 400 470 350 365 270 550 530
The following data represent a random sample of five measurements from a normally distributed population: 7,4,2,5,7 a. Find 90% confidence interval for u. b. Find a 99% confidence interval for u.
A survey finds that the prices paid for two-year-old Ford Fusion cars are normally distributed with a mean of $17,500.00 and a standard deviation of $500.00. Consider a sample of 10,000 people who bought two-year-old Ford Fusions. 6800 of the people who bought two-year old Ford Fusions spends between $ .00 and $ .00 How many people spends less than $17,000.00 people. How many people spends more than $19,000.00 people (Note this question has to do with the empirical rule and the symmetric nature of the normal distribution)
A recent report indicated a typical family spend $650 per month on food. Assume the distribution of food expenditures for a family of five follows a normal distribution, with mean of $650 and standard deviation of $120. A sample of 64 is taken. a) What percentage of the families spends more than $675 per month on food? b) What percentage of the families spends less than $660 per month on food? c) What percentage of the families spends between $660 and $670 per month on food? d) What percentage of the families spends less than $650 or more than $675 per month on
2) Construct a 95% confidence interval for the population mean, μ. Assume the population has a normal distribution. A sample of 20 part-time workers had mean annual earnings of $3120 with a standard deviation of $677. Round to the nearest dollar.
Answer.
1. Find the sample standard deviation from the following data. 1420,1223,988,694,730,836,721,742,541,623,1449,950 2., Construct a 99%confidence interval for the population mean μ.