8. The following redox reaction occurs at 25.0°C: 5F22*(aq) + MnO4 (aq) + 8H*(aq) → Mn2 (aq) + 4H20(1) + 5FE³*(aq) a. Calculate the E°cell for the redox reaction. Half Reaction E(V) MnOa (aq) + 8H*(aq) + 5e → Mn²*(aq) + 4H20(I) Fe3 (aq) + e → Fe2*(aq) +1.51 +0.77 b. Calculate the AG° in kJ/mol at 25.0°C.
8. The following redox reaction occurs at 25.0°C: 5F22*(aq) + MnO4 (aq) + 8H*(aq) → Mn2 (aq) + 4H20(1) + 5FE³*(aq) a. Calculate the E°cell for the redox reaction. Half Reaction E(V) MnOa (aq) + 8H*(aq) + 5e → Mn²*(aq) + 4H20(I) Fe3 (aq) + e → Fe2*(aq) +1.51 +0.77 b. Calculate the AG° in kJ/mol at 25.0°C.
Chemistry
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![8. The following redox reaction occurs at 25.0°C:
5F22*(aq) + MnO4 (aq) + 8H*(aq) → Mn²*(aq) + 4H2O(1) + 5FE³*(aq)
a.
Calculate the E°cell for the redox reaction.
Half Reaction
E(V)
MnO4 (aq) + 8H*(aq) + 5e¨ → Mn²*(aq) + 4H2O(1I)
Fe3 (aq) + e → Fe2*(aq)
+1.51
+0.77
b. Calculate the AG° in kJ/mol at 25.0°C.
Calculate the AG when the following concentrations are used at 25.0°C.
[Fe?*] = 0.200 M
[MnO4] = 0.440M
[H*] = 0.200 M
[Mn2*] = 0.750 M
[Fe3*] = 0.850 M
с.
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Transcribed Image Text:8. The following redox reaction occurs at 25.0°C:
5F22*(aq) + MnO4 (aq) + 8H*(aq) → Mn²*(aq) + 4H2O(1) + 5FE³*(aq)
a.
Calculate the E°cell for the redox reaction.
Half Reaction
E(V)
MnO4 (aq) + 8H*(aq) + 5e¨ → Mn²*(aq) + 4H2O(1I)
Fe3 (aq) + e → Fe2*(aq)
+1.51
+0.77
b. Calculate the AG° in kJ/mol at 25.0°C.
Calculate the AG when the following concentrations are used at 25.0°C.
[Fe?*] = 0.200 M
[MnO4] = 0.440M
[H*] = 0.200 M
[Mn2*] = 0.750 M
[Fe3*] = 0.850 M
с.
%3D
%3D
%3D
Expert Solution
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Introduction
Electrochemistry is the branch of chemistry which studies the change of chemical energy into electrical energy during a chemical energy. Standard electrode potential is the potential of the individual electrode which can be determined experimentally. It is represented by. Its unit is Volt (V).
Given data
Faraday’s constant, F = 96500 C mol-1
No. of electrons, n = 5
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