**Problem 35: Balancing a Redox Reaction under Basic Aqueous Conditions**In this problem, we are tasked with balancing the following redox reaction that takes place in a basic aqueous environment:\[ \text{MnO}_4^-(aq) + \text{SO}_3^{2-}(aq) \rightarrow \text{MnO}_2(s) + \text{SO}_4^{2-}(aq) \]**Steps to Balance the Redox Reaction:**1. **Identify the Half-Reactions:** - **Reduction Half-Reaction:** \(\text{MnO}_4^- \rightarrow \text{MnO}_2\) - **Oxidation Half-Reaction:** \(\text{SO}_3^{2-} \rightarrow \text{SO}_4^{2-}\)2. **Balance Atoms Other than \(O\) and \(H\):** - Manganese is already balanced in the reduction half-reaction. - Sulfur is balanced in the oxidation half-reaction.3. **Balance Oxygen Atoms by Adding \(H_2O\):** - For the reduction half-reaction: \(\text{MnO}_4^- \rightarrow \text{MnO}_2 + 2H_2O\) - For the oxidation half-reaction: \(\text{SO}_3^{2-} + H_2O \rightarrow \text{SO}_4^{2-}\)4. **Balance Hydrogen Atoms by Adding \(OH^-\):** - Reduction Half-Reaction: Add \(4OH^-\) to the right side to balance hydrogen. - Oxidation Half-Reaction: Add \(2OH^-\) to the left side.5. **Combine the Balanced Half-Reactions:** - Reduction: \(\text{MnO}_4^- + 2H_2O + 4OH^- \rightarrow \text{MnO}_2 + 4OH^-\) - Oxidation: \(\text{SO}_3^{2-} + H_2O + 2OH^- \rightarrow \text{SO}_4^{2-} + 2OH^-\)6. **Balance Charges by Adding Electrons:** - Add electrons to balance the charges in each half-reaction, then multiply and combine the half-reactions

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Answered: . Balance the following redox reaction…

Science

Chemistry

. Balance the following redox reaction under basic aqueous conditions. MnO4 (aq) + SO3²(aq) -> MnO2(s) + SO,²(aq)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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