When an aqueous solution of potassium iodide is electrolyzed using platinum electrodes, the half-reactions are 2I–(aq) → I2(aq) + 2e– 2H2O(l) + 2e– → H2(g) + 2OH–(aq) How many grams of iodine are produced when a current of 8.15 mA flows through the cell for 12.6 min (756 s)?
When an aqueous solution of potassium iodide is electrolyzed using platinum electrodes, the half-reactions are 2I–(aq) → I2(aq) + 2e– 2H2O(l) + 2e– → H2(g) + 2OH–(aq) How many grams of iodine are produced when a current of 8.15 mA flows through the cell for 12.6 min (756 s)?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 120AE
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When an aqueous solution of potassium iodide is electrolyzed using platinum electrodes,
the half-reactions are
2I–(aq) → I2(aq) + 2e–
2H2O(l) + 2e– → H2(g) + 2OH–(aq)
How many grams of iodine are produced when a current of 8.15 mA flows through the
cell for 12.6 min (756 s)?
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