8. The figure shows a horizontal beam of light that is incident upon a prism, where the base of the prism is also horizontal. The prism has an index of refraction of 1.31 and is surrounded by oil with an index of refraction of 1.48. (a) Determine the angle 0 that the exiting light makes with the normal to the right face of the prism as shown in the figure. (b) Determine the speed of light in the oil. (c) Determine the speed of light in the prism. NOTE: the angles in the figure are only representative! The actual angles may be larger or smaller than what are shown in the figure. 63⁰ /54° 18

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**Problem 8: Optics of a Prism**

A horizontal beam of light is incident upon a prism, whose base is horizontal. The prism has an index of refraction of 1.31 and is surrounded by oil with an index of refraction of 1.48.

**Tasks:**

(a) **Angle Calculation:** Determine the angle θ that the exiting light makes with the normal to the right face of the prism as shown.

(b) **Speed of Light in Oil:** Calculate the speed of light in the oil.

(c) **Speed of Light in the Prism:** Determine the speed of light in the prism.

**Note:** The angles in the figure are only representative. Actual angles may vary.

**Diagram Description:**

- The prism is a triangular shape with one angle labeled 54°.
- The angles adjacent to the base of the prism are each labeled 63°.
- An incoming light ray is shown entering the prism horizontally from the left.
- The exiting ray forms an angle θ with the normal on the right side of the prism.

**Key Concepts:**

- **Index of Refraction (\(n\)):** A measure of how much the speed of light is reduced inside a medium.
- **Snell’s Law:** Used to calculate the refraction angles and involves the indices of refraction of different media.

**Solution Approach:**

1. Use Snell’s Law to find the refraction angles between oil and prism.
2. Apply the relationship between speed of light (\(c\)), index of refraction (\(n\)), and speed in medium (\(v = \frac{c}{n}\)) to find speeds in oil and prism.
Transcribed Image Text:**Problem 8: Optics of a Prism** A horizontal beam of light is incident upon a prism, whose base is horizontal. The prism has an index of refraction of 1.31 and is surrounded by oil with an index of refraction of 1.48. **Tasks:** (a) **Angle Calculation:** Determine the angle θ that the exiting light makes with the normal to the right face of the prism as shown. (b) **Speed of Light in Oil:** Calculate the speed of light in the oil. (c) **Speed of Light in the Prism:** Determine the speed of light in the prism. **Note:** The angles in the figure are only representative. Actual angles may vary. **Diagram Description:** - The prism is a triangular shape with one angle labeled 54°. - The angles adjacent to the base of the prism are each labeled 63°. - An incoming light ray is shown entering the prism horizontally from the left. - The exiting ray forms an angle θ with the normal on the right side of the prism. **Key Concepts:** - **Index of Refraction (\(n\)):** A measure of how much the speed of light is reduced inside a medium. - **Snell’s Law:** Used to calculate the refraction angles and involves the indices of refraction of different media. **Solution Approach:** 1. Use Snell’s Law to find the refraction angles between oil and prism. 2. Apply the relationship between speed of light (\(c\)), index of refraction (\(n\)), and speed in medium (\(v = \frac{c}{n}\)) to find speeds in oil and prism.
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