8. A chemistry student weighed a piece of chalk and found that it had amass of 56.7 g. After a day of writing with the chalk, the mass decreased4 pointto 48.3 g. How many moles of chalk were used? The chemical formula forchalk is CaC03.*O 0.483 molesO 0,0839 molesO 8.4 moles841 molesOther:9.What is the balanced equation for the decomposition of iron(II)hydrogen carbonate? *3 points2Fe(HCO)3 (s) ---> Fe2(CO3)3 (s) + H2O (1) + CO2(g)Fe(HCO)3 (s) –> Fe2(C03)3 (s) + H20 (1) + C02(g).2Fe(HCO)3 (s) --> Fe2(C03)3 (s) + 3 H20 (1) + 3 CO2(g)2Fe(HCO)3 (s) ---> Fe(C03)3 (s) +3 H20 (1) + 3 CO2(g)Other:

Given in the question, Mass of chalk before using = 56.7 gm Mass of chalk after using = 48.3 gm Mass…

8. A chemistry student weighed a piece of chalk and found that it had a mass of 56.7 g. After a day of writing with the chalk, the mass decreased to 48.3 g. How many moles of chalk were used? The chemical formula for chalk is CaCO3. *

8. A chemistry student weighed a piece of chalk and found that it had a mass of 56.7 g. After a day of writing with the chalk, the mass decreased to 48.3 g. How many moles of chalk were used? The chemical formula for chalk is CaCO3. *

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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