6. Consider the reaction of solid PbO and gaseous NH₃ to form solid Pb, nitrogen gas, and water vapor. a. The balanced chemical equation is 3 PbO(s) + 2 NH₃(g) → 3 Pb(s) + N₂(g) + 3 H₂O(g). How many moles of NH₃ are required to produce 185.6 grams of Pb based on the balanced chemical equation?  b. How many grams of N₂ will be produced from 0.447 moles of PbO balanced chemical equation?   c. How many grams of NH₃ will be required to react with 32.7 grams of PbO based on the balanced chemical equation? (Part a shown in picture)

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6. Consider the reaction of solid PbO and gaseous NH₃ to form solid Pb, nitrogen gas, and water vapor.

a. The balanced chemical equation is 3 PbO(s) + 2 NH₃(g) → 3 Pb(s) + N₂(g) + 3 H₂O(g). How many moles of NH₃ are required to produce 185.6 grams of Pb based on the balanced chemical equation? 
b. How many grams of N₂ will be produced from 0.447 moles of PbO balanced chemical equation?
 
c. How many grams of NH₃ will be required to react with 32.7 grams of PbO based on the balanced chemical equation?
(Part a shown in picture)
STARTING AMOUNT
X
Consider the reaction of solid PbO and gaseous NH3 to form solid Pb, nitrogen
gas, and water vapor.
The balanced chemical equation is 3 PbO(s) + 2 NH3(g) 3 Pb(s) + N₂(g) + 3 H₂O(g).
How many moles of NH3 are required to produce 185.6 grams of Pb based on the
balanced chemical equation?
17.03
ADD FACTOR
x( )
123.7
g Pb
185.6
3
g NH3/mol NH3
0.7443
10.17
g NH3
ANSWER
207.2
1.344
mol NH3
0.5972
0.8958
g Pb/mol Pb
1
RESET
5
mol Pb
2
Transcribed Image Text:STARTING AMOUNT X Consider the reaction of solid PbO and gaseous NH3 to form solid Pb, nitrogen gas, and water vapor. The balanced chemical equation is 3 PbO(s) + 2 NH3(g) 3 Pb(s) + N₂(g) + 3 H₂O(g). How many moles of NH3 are required to produce 185.6 grams of Pb based on the balanced chemical equation? 17.03 ADD FACTOR x( ) 123.7 g Pb 185.6 3 g NH3/mol NH3 0.7443 10.17 g NH3 ANSWER 207.2 1.344 mol NH3 0.5972 0.8958 g Pb/mol Pb 1 RESET 5 mol Pb 2
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