8. A= C}) A-人エ=C入)=0 (-人)(-1-)@(-5)x2=0 1一人 ー5 入=±3 人」=3え A-人エ=/ -3 -5 2 +3i 区 CA-人りぶ=0 ブ=() C13i)a-sb=0 A a=5, b=CF3i) 2at (--3)b=0 エ=e(シ=Cossat sSsey L) %3D -2- %3D Cosat3Sin3at isinšz-3ilasta) 56532 ニ 人=ーろ A人I=C'5)-)=/ #34 -5 (AI)=0 -3i o ce - 2 13シ CH32)a-53=0 20 +(1+30)6=0 五-ビ し)= Cosxns) Ct) 5 ニ Co33スt35m以Sスナ3ia3ス C os43s) +(ル So the general solution of this question es ニ 5 Co53X 九F ししos3xta) t Caし shx-3084 $5m 3ス

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Is there anything wrong with steps of the third question? 

Sし
8.X=
ニ
2.
-5
A= C:
A-人エ=Cヶ入)=0
(1-入)(-1-)金C-5)×2=0
2-1
1-1
2 1-1
东
入=±3i
n in Figure 16.6. Sup
A-人I= / 1-3t -5
2 +3i,
人,=3も
区
A人エ=
ニ
C13i)a-sb=D0
a=5, b=C+3i)
2at (--3)b=0
1=1
5
こ
-2-
tions (32) in terms
Cossact 3 Srinsat isinsz-3ilosta)
5C0532
55in3e
V(0) = 3 V.
(1) and V(1) as 1-
ニ
2ニー36
A-do I= ('s)-C
tial conditions?
2-1,
2 737;
2
Henve
(A-)=0
{
ES
a
2a +G1+3)6=0
V2=
ニ
ス=
龙:
5
%3D
よ
13
5 Cos3X 5isin3x
C
blem 20.
is describel
560532
+1
2.
So the general solutibn of this
queshiom is
5 cos3X
0 しし cos3xt3sul t し2L sn3t-303%4
Vis te
ons wer
man
Transcribed Image Text:Sし 8.X= ニ 2. -5 A= C: A-人エ=Cヶ入)=0 (1-入)(-1-)金C-5)×2=0 2-1 1-1 2 1-1 东 入=±3i n in Figure 16.6. Sup A-人I= / 1-3t -5 2 +3i, 人,=3も 区 A人エ= ニ C13i)a-sb=D0 a=5, b=C+3i) 2at (--3)b=0 1=1 5 こ -2- tions (32) in terms Cossact 3 Srinsat isinsz-3ilosta) 5C0532 55in3e V(0) = 3 V. (1) and V(1) as 1- ニ 2ニー36 A-do I= ('s)-C tial conditions? 2-1, 2 737; 2 Henve (A-)=0 { ES a 2a +G1+3)6=0 V2= ニ ス= 龙: 5 %3D よ 13 5 Cos3X 5isin3x C blem 20. is describel 560532 +1 2. So the general solutibn of this queshiom is 5 cos3X 0 しし cos3xt3sul t し2L sn3t-303%4 Vis te ons wer man
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