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8 Write the net cell for this electroche equation Phases one optional. Do not include concentrations, 24 reaction: Curss | Cur ↑ CAg CUTE Ag² → Ag <-Cu² Teacont 2+ (0.0155 M)|| Agt (aq, 3.50m) | Ages) + reactant prodret product anode oxidation = AG 16 rn = Ecell E cell - 0.46 → Ag reduction = +0.34 V +0.80 V / Ecell (0.80) 0.34 = 0.467 = 3.50 M [²] = Erell Ecell (0.46)-(0.0592 0.0155 M >#?

8 Write the net cell for this electroche equation Phases one optional. Do not include concentrations, 24 reaction: Curss | Cur ↑ CAg CUTE Ag² → Ag <-Cu² Teacont 2+ (0.0155 M)|| Agt (aq, 3.50m) | Ages) + reactant prodret product anode oxidation = AG 16 rn = Ecell E cell - 0.46 → Ag reduction = +0.34 V +0.80 V / Ecell (0.80) 0.34 = 0.467 = 3.50 M [²] = Erell Ecell (0.46)-(0.0592 0.0155 M >#?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I got stuck. I'm not sure how to go about determining n. Is it how many moles were in the reaction? 

Phases Write the net cell equation for this electrochemical cell. ore optional. Do not include concentrations, 2+ reaction: Cucs) | Cu² (09, (0.0155 M/| Agt (aq, 3.50m) | Ag(s) ↑ A Teadant product anode product 2+ → Cu²+ oxidation = + 0.34 V (5) cathode -reduction = Ag → Ag, (5) + 0.80 V 14641 anode Ecell (0.80) - 0.34 = 0.467 AG AG rvm= Ecell = E cell 0.46 Сад'] = 3.50 м сQu2+] = 0.0155 м M M Erell Ecell = (0.46)-(0.0592 n reactant #? ✓
Transcribed Image Text:Phases Write the net cell equation for this electrochemical cell. ore optional. Do not include concentrations, 2+ reaction: Cucs) | Cu² (09, (0.0155 M/| Agt (aq, 3.50m) | Ag(s) ↑ A Teadant product anode product 2+ → Cu²+ oxidation = + 0.34 V (5) cathode -reduction = Ag → Ag, (5) + 0.80 V 14641 anode Ecell (0.80) - 0.34 = 0.467 AG AG rvm= Ecell = E cell 0.46 Сад'] = 3.50 м сQu2+] = 0.0155 м M M Erell Ecell = (0.46)-(0.0592 n reactant #? ✓
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To calculate Δ?rxn = Δ?rxn° + RTln Q ; how would I calculate for Q?

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