+8 V- +4 V- 4 5 +6V- 2 4 A↑ 1A 2A 6 1A 3 A +12 V- + + 116 V 10 V 3 7 -7V + 8 Figure P1.27 Circuit for Problem 1.27.
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For each of the eight devices in the circuit of Fig. P1.27, determine whether the device is a supplier or a recipient of power and how much power it is supplying or receiving
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- 5a. What is E2=? 5b. What is E3=? 5c. What is the potential difference of b relative to point a (V_ba)?Please someone help me to slove these two problems, and give me an explanation , thank youShown in the figure below is an electrical circuit containing three resistors and two batteries. 13 www R₁ ww R3 R₂ www 1₂ • R₁ =90 • R₂ = 60 • R₂ = 10 Write down the Kirchhoff Junction equation and solve it for I, in terms of 12 and 13. Write the result here: I₁ = Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise. 0 = X The resistors in the circuit have the following values: 10 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components R₁, R₂, and 4V. 0=R₁₁+R₂1₂-4 Amperes Amperes Amperes 4 Solve for all the following (some answers may be negative): I₁ = 1₂ = | 13 = NOTE: For the equations, put in resistances and currents SYMBOLICALLY using variables like R₁,R₂,R3 and 1₁,12,13. Use numerical values of 10 and 4 for the voltages.
- Shown in the figure below is an electrical circuit containing three resistors and two batteries. R3 10 R2 R1 Write down the Kirchhoff Junction equation and solve it for I, in terms of I, and Iz. Write the result here: Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise. Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components R1, R2, and 4V. The resistors in the circuit have the following values: R, = 130 • R2 = 50 R3 = 10 Solve for all the following (some answers may be negative): | Amperes I = I, = Amperes Iz = Amperes NOTE: For the equations, put in resistances and currents SYMBOLICALLY using variables like RR2,R3 and I,,12,13. Use numerical values of 10 and 4 for the voltages.If /1 goes to the right through R1, 12 goes to the right through R2, and /3 goes to the right through R3, what is the resulting equation resulting from applying Kirchhoff's junction rule at point b? Please show solution not only ansSwer. 8.0V R 9.0 V a5) please solve, will upvote!
- For R1=55, R2=D125, R33D135, R4=15, R5=40, R63D90 and V1=4 V in the shown figure, use circuit reduction and current/voltage division rules to calculate the following: R6 R1 R5 R3 R2 V1 V2 R4 V13= V2=R₁ =1292 Igc = 0.16A IDC = Problem #21) Determine the source current Ipc and the resistor voltage V4 as shown in the following circuit using the Reduce and Return Method if the source voltage is Vpc = 72 volts. R₂=402 R₁ =1552 R₁=4592 0.16 IDC =. V₁=. 2 (A) 36 (A) (V)Convert the following problem to standard form and solve. Maximize x1 + 4x2 + X3 Subject to 2x1 – 2x2 + X3 = 4 x1 – x3 = 1 x2 2 0, x3 > 3.
- My first guess was D1 is reverse bias and D2 is forward bias. So, I redrew the circuit, opening D1 and changing D2 to a Vs = 0.5. Then, I'm solving for Vout. What do I do next, and am I supposed to redraw the circuit four times? I'm confused how to continue solving this problem and how to graph it afterwards.Can you provide detailed explanation for each step you make?What is the function of the circuit shown in Figure 9? CLR CLK (9) (8) (2) R PR (3) lo S bHR Q₁ S bR bR (5) Q₂ S Figure 9 (6) 23 S PR (10) 24 PR (11) Q5 S PR (12) 26 S (13) 27can you explain to me why the convolution of these two sinc fucntions which are rect functions equal a rect function? I thought when you convolute a rectangle and a rectangle with two different lengths, it makes a trapezoid shape. The answer says it is rectangle funtion so my code is corrcect but i dont understand why this is true. I need a step by step solution and explanation. here is the problem: Consider the signal x(t) = 2 sinc(6t + 3).the output y (t) = (x *h )(t) when x(t) ispassed through a filter with impulse response h (t) = 4sinc(2t -1). the matlab code was just to help me visuallize