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8 A sample of 2.05 g of polystyrene of uniform polymer chain length was dissolved in enough toluene to form 0.100 Lc solution. The osmotic pressure of this solution was found to be 1.21 kPa at 25°C. Calculate the molar mass of the polystyrene. a) O 2.35 x 10* g/mol b) 4.20x 10 g/mol C) 3.05 x 105 g/mo 4.20x 103 g/mol 4.20 x 10 g/mol

8 A sample of 2.05 g of polystyrene of uniform polymer chain length was dissolved in enough toluene to form 0.100 Lc solution. The osmotic pressure of this solution was found to be 1.21 kPa at 25°C. Calculate the molar mass of the polystyrene. a) O 2.35 x 10* g/mol b) 4.20x 10 g/mol C) 3.05 x 105 g/mo 4.20x 103 g/mol 4.20 x 10 g/mol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A sample of 2.05 g of polystyrene of uniform polymer chain length was dissolved in enough toluene to form 0.100 L of solution. The osmotic pressure of this solution was found to be 1.21 kPa at 25°C. Calculate the molar mass of the polystyrene. 8 - a) 2.35 x 10 g/mol b) 4.20x 10 g/mol 3.05 x 10 g/mo 4.20x 103 g/mol 4.20 x 10 g/mol Boş bırak KÖnceki 8/20 Sonraki> Карat
Transcribed Image Text:A sample of 2.05 g of polystyrene of uniform polymer chain length was dissolved in enough toluene to form 0.100 L of solution. The osmotic pressure of this solution was found to be 1.21 kPa at 25°C. Calculate the molar mass of the polystyrene. 8 - a) 2.35 x 10 g/mol b) 4.20x 10 g/mol 3.05 x 10 g/mo 4.20x 103 g/mol 4.20 x 10 g/mol Boş bırak KÖnceki 8/20 Sonraki> Карat
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