At 300°K, the vapor pressure of pure benzene (C6H6) is 0.1355 atm and the vapor pressure of pure n-hexane (C6H14) is 0.2128 atm. Mixing 50.0 g benzene with 50.0 g of n-hexane gives a solution that is nearly ideal. If this vapor were collected and then recondensed, the mole fraction of benzene in this new solution would be 0.414. If the new solution were allowed to come to equilibrium, what would the mole fraction of benzene in the vapor in equilibrium with the solution be?
At 300°K, the vapor pressure of pure benzene (C6H6) is 0.1355 atm and the vapor pressure of pure n-hexane (C6H14) is 0.2128 atm. Mixing 50.0 g benzene with 50.0 g of n-hexane gives a solution that is nearly ideal. If this vapor were collected and then recondensed, the mole fraction of benzene in this new solution would be 0.414. If the new solution were allowed to come to equilibrium, what would the mole fraction of benzene in the vapor in equilibrium with the solution be?
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.26QE
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At 300°K, the vapor pressure of pure benzene (C6H6) is 0.1355 atm and the vapor pressure of pure n-hexane (C6H14) is 0.2128 atm. Mixing 50.0 g benzene with 50.0 g of n-hexane gives a solution that is nearly ideal. If this vapor were collected and then recondensed, the mole fraction of benzene in this new solution would be 0.414. If the new solution were allowed to come to equilibrium, what would the mole fraction of benzene in the vapor in equilibrium with the solution be?
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