**Problem 5 (7%)** A hammer of mass \( m = 0.46 \, \text{kg} \) is moving horizontally at a velocity of \( v = 5.5 \, \text{m/s} \) when it strikes a nail and comes to rest after driving the nail a distance \( \Delta x = 1.25 \, \text{cm} \) into a board.---### 50% Part (a)**Question:** What is the duration of the impact, in seconds, assuming the acceleration of the hammer was constant?**Answer Box:** \( \Delta t = \) [Input Field]---### Keypad Options:- Trigonometric functions: \( \sin() \), \( \cos() \), \( \tan() \)- Reciprocal functions: \( \cotan() \), \( \asin() \), \( \acos() \)- Equal counterparts: \( \atan() \), \( \acotan() \), \( \sinh() \)- Hyperbolic functions: \( \cosh() \), \( \tanh() \), \( \cotanh() \)- Constants: \( \pi \)- Numeric Keys: \( 7 \), \( 8 \), \( 9 \), \( 4 \), \( 5 \), \( 6 \), \( 1 \), \( 2 \), \( 3 \), \( 0 \)- Arithmetic operations and other functions: \( \cdot, +, -, \sqrt{} \)- Controls: BACKSPACE, DELETE, CLEAR, HOME, END- **Radio Buttons:** Degrees / Radians**Submission Options:** - Submit button - Hint (3% deduction per hint, 2 hints remaining) - Feedback (2% deduction per feedback) - I give up!---### 50% Part (b)**Question:** What was the average force, in newtons, exerted on the nail?---*Note: Ensure calculations are performed assuming constant acceleration for accurate results.*

Given m = 0.46 kg v = 5.5 m/s x = 0.0125 ma) v' = ( v2 + 2a*x)1/2 0= ( 5.52 + 2a *0.0125) 1/2 a = - 1210 m /s2 Now t = - v /a = - 5.5 / ( -1210) = 0.00413 sb) F = m*v / t = 0.46* 5.5 / 0.00413 = 612.26 N

Answered: (7%) Problem 5: A hammer of mass m=…

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(7%) Problem 5: A hammer of mass m= 0.46 kg is moving horizontally at a velocity of v = 5.5 m/s when it strikes a nail and comes to rest after driving the nail a distance Ax = 1.25 cm into a board.