2. Earth is rotating about the Sun in our solar system. The distance between the Earth and Sun is 1.5 x 10"m. Consider the impact of an asteroid of mass 8.9 x105 kg and a speed of 90,000 km/h with respect to the Earth's surface. The asteroid strikes the Earth at the equator as shown in Figure. Consider the mass and radius of the Earth are Mg = 5.97 x 104 kg and Rg = 6.38 x10 m, respectively. Assume that the axial and orbital axis of rotations are parallel to each other. Earth North Pole (a) Calculate the axial and total angular momentum of the Earth. (b) What is the change in the angular velocity of the Earth due to the collision? (c) What is the maximum possible change in the length of a day due to the collision? (d) How much energy is needed to stop the Earth's rotation about its axis after the collision? (e) What would be the moment of inertia of the Earth if the axis of rotation is parallelly shifted so that it touches the equator? た

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2. Earth is rotating about the Sun in our solar system. The distance between the Earth and Sun
is 1.5 x 10"m. Consider the impact of an asteroid of mass 8.9 x105 kg and a speed of 90,000
km/h with respect to the Earth's surface. The asteroid strikes the Earth at the equator as shown
in Figure. Consider the mass and radius of the Earth are Mg = 5.97 x 1024 kg and RE = 6.38
x10° m, respectively. Assume that the axial and orbital axis of rotations are parallel to each
other.
Earth
North Pole
(a) Calculate the axial and total angular momentum of the Earth.
(b) What is the change in the angular velocity of the Earth due to the collision?
(c) What is the maximum possible change in the length of a day due to the collision?
(d) How much energy is needed to stop the Earth's rotation about its axis after the collision?
(e) What would be the moment of inertia of the Earth if the axis of rotation is parallelly
shifted so that it touches the equator?
Transcribed Image Text:2. Earth is rotating about the Sun in our solar system. The distance between the Earth and Sun is 1.5 x 10"m. Consider the impact of an asteroid of mass 8.9 x105 kg and a speed of 90,000 km/h with respect to the Earth's surface. The asteroid strikes the Earth at the equator as shown in Figure. Consider the mass and radius of the Earth are Mg = 5.97 x 1024 kg and RE = 6.38 x10° m, respectively. Assume that the axial and orbital axis of rotations are parallel to each other. Earth North Pole (a) Calculate the axial and total angular momentum of the Earth. (b) What is the change in the angular velocity of the Earth due to the collision? (c) What is the maximum possible change in the length of a day due to the collision? (d) How much energy is needed to stop the Earth's rotation about its axis after the collision? (e) What would be the moment of inertia of the Earth if the axis of rotation is parallelly shifted so that it touches the equator?
1. A wood block of mass mw = 200 g is projected from the ground at a speed vo = 35 m/s and
at an angle 6b = 50°. When at height h = 24 m the wood block was hit by a bullet of mass m, =
25 g which was moving at v = 220 m/s and at an angle 6 = 70°. After the collision, the bullet
embedded itself in the block and move together and land at point A on the ground. Then they
move on the ground that has coefficient of kinetic friction µe = 0.5 and start to compress a
horizontal spring at point B. The distance between point A and B is 18 m and the spring
constant k = 3x10° N/m. Right end of the spring is fixed, and all motions are confined in x-y
plane.
Wood block
+ Bullet
Bullet
to
Wood
A
block
(a) Was the collision between the wood block and the bullet elastic or inelastic?
Explain quantitively
(b) Find the maximum height from the ground the block with the bullet reached.
(c) How far is point A from the launch point of the wood block?
(d) Calculate the velocity at which the block-bullet system lands at point A. What will be the
speed of it at point B?
(e) Determine how much the spring will be compressed when the block-bullet system comes
to a rest.
Page 1 of 2
Transcribed Image Text:1. A wood block of mass mw = 200 g is projected from the ground at a speed vo = 35 m/s and at an angle 6b = 50°. When at height h = 24 m the wood block was hit by a bullet of mass m, = 25 g which was moving at v = 220 m/s and at an angle 6 = 70°. After the collision, the bullet embedded itself in the block and move together and land at point A on the ground. Then they move on the ground that has coefficient of kinetic friction µe = 0.5 and start to compress a horizontal spring at point B. The distance between point A and B is 18 m and the spring constant k = 3x10° N/m. Right end of the spring is fixed, and all motions are confined in x-y plane. Wood block + Bullet Bullet to Wood A block (a) Was the collision between the wood block and the bullet elastic or inelastic? Explain quantitively (b) Find the maximum height from the ground the block with the bullet reached. (c) How far is point A from the launch point of the wood block? (d) Calculate the velocity at which the block-bullet system lands at point A. What will be the speed of it at point B? (e) Determine how much the spring will be compressed when the block-bullet system comes to a rest. Page 1 of 2
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