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71. ssm A 15-g bullet is fired from a rifle. It takes 2.50 X 10-3 s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 715 m/s. Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet.

71. ssm A 15-g bullet is fired from a rifle. It takes 2.50 X 10-3 s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 715 m/s. Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Ch.4 #71 . Please see attached image for Physics question . Thank you

**Problem 71:** A 15-g bullet is fired from a rifle. It takes \(2.50 \times 10^{-3}\) seconds for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 715 m/s. Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet. --- **Solution Approach:** 1. **Given Data:** - Mass of the bullet (\(m\)) = 15 g = 0.015 kg (convert to kilograms). - Time (\(t\)) = \(2.50 \times 10^{-3}\) seconds. - Final velocity (\(v\)) = 715 m/s. - Initial velocity (\(u\)) = 0 m/s (assuming the bullet starts from rest). 2. **Find Acceleration (\(a\)):** - Use the formula: \[ v = u + at \] - Rearrange to solve for acceleration (\(a\)): \[ a = \frac{v - u}{t} \] 3. **Calculate Force (\(F\)):** - Use Newton's second law: \[ F = ma \] Calculate \(a\) and subsequently \(F\) using the given values. This will provide the average net force exerted on the bullet.
Transcribed Image Text:**Problem 71:** A 15-g bullet is fired from a rifle. It takes \(2.50 \times 10^{-3}\) seconds for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 715 m/s. Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet. --- **Solution Approach:** 1. **Given Data:** - Mass of the bullet (\(m\)) = 15 g = 0.015 kg (convert to kilograms). - Time (\(t\)) = \(2.50 \times 10^{-3}\) seconds. - Final velocity (\(v\)) = 715 m/s. - Initial velocity (\(u\)) = 0 m/s (assuming the bullet starts from rest). 2. **Find Acceleration (\(a\)):** - Use the formula: \[ v = u + at \] - Rearrange to solve for acceleration (\(a\)): \[ a = \frac{v - u}{t} \] 3. **Calculate Force (\(F\)):** - Use Newton's second law: \[ F = ma \] Calculate \(a\) and subsequently \(F\) using the given values. This will provide the average net force exerted on the bullet.
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