7.(a) Draw and label (i) the enantiomer and (ii) a pair of diasteromers of the following compound. он (b) Will a 50:50 mix of the enantiomers that you drew for 7al be optically active (rotate plane polarized light). Explain the reason for your answer
7.(a) Draw and label (i) the enantiomer and (ii) a pair of diasteromers of the following compound. он (b) Will a 50:50 mix of the enantiomers that you drew for 7al be optically active (rotate plane polarized light). Explain the reason for your answer
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 7:**
**(a)** Draw and label (i) the enantiomer and (ii) a pair of diastereomers of the following compound.
*The structure shown is a cyclohexane ring with an OH group and an NH₂ group attached. The OH group is represented with a solid wedge, indicating it is on the front face of the ring, while the NH₂ group is shown with a dashed wedge, indicating it is on the back face of the ring.*
**(b)** Will a 50:50 mix of the enantiomers that you drew for 7a(i) be optically active (rotate plane polarized light)? Explain the reason for your answer.
**(b)** Will a 50:50 mix of the two diastereomers you drew for 7a(ii) be optically active (rotate plane polarized light)? Explain the reason for your answer.
**Explanation:**
- **Enantiomers** are mirror images of each other that cannot be superimposed. A 50:50 mix of enantiomers is called a racemic mixture and it is not optically active because the optical rotations of the enantiomers cancel each other out.
- **Diastereomers** are not mirror images and usually do not have identical properties. A 50:50 mix of diastereomers generally does not result in optical inactivity, and such a mixture may still be optically active depending on the specific structure and arrangement of the molecules.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fce0afc3b-3e57-4487-b673-cf6f07e8890b%2F14e28c1e-5e44-4d17-875d-d60af4fff157%2F3y0dvtv_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 7:**
**(a)** Draw and label (i) the enantiomer and (ii) a pair of diastereomers of the following compound.
*The structure shown is a cyclohexane ring with an OH group and an NH₂ group attached. The OH group is represented with a solid wedge, indicating it is on the front face of the ring, while the NH₂ group is shown with a dashed wedge, indicating it is on the back face of the ring.*
**(b)** Will a 50:50 mix of the enantiomers that you drew for 7a(i) be optically active (rotate plane polarized light)? Explain the reason for your answer.
**(b)** Will a 50:50 mix of the two diastereomers you drew for 7a(ii) be optically active (rotate plane polarized light)? Explain the reason for your answer.
**Explanation:**
- **Enantiomers** are mirror images of each other that cannot be superimposed. A 50:50 mix of enantiomers is called a racemic mixture and it is not optically active because the optical rotations of the enantiomers cancel each other out.
- **Diastereomers** are not mirror images and usually do not have identical properties. A 50:50 mix of diastereomers generally does not result in optical inactivity, and such a mixture may still be optically active depending on the specific structure and arrangement of the molecules.
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