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7.3.1 - What bit positions (7 to 0) in R4 will be cleared when the following instruction is executed? bic.b #11110000b, R4

7.3.1 - What bit positions (7 to 0) in R4 will be cleared when the following instruction is executed? bic.b #11110000b, R4

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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### Bitwise Operations in Assembly Language #### 7.3.1 - What bit positions (7 to 0) in R4 will be cleared when the following instruction is executed? ``` bic.b #11110000b, R4 ``` - ⃝ 0, 1, 2, 3, 4, 5, 6, and 7 - ⃝ 4, 5, 6, and 7 - ⃝ 0 - ⃝ 0, 1, 2, and 3 #### Explanation: The `bic` instruction stands for "bit clear". It performs a bitwise AND operation on the value in register R4 with the inverse of the immediate value provided (`#11110000b`). Here's the step-by-step analysis for the given operation: - The immediate value `11110000b` is binary for 240 in decimal. - Inverting `11110000b` gives us `00001111b`. - The `bic` operation will clear bits in R4 where the inverse value (`00001111b`) has a 1. Therefore, this operation will clear the bit positions 0, 1, 2, and 3 in register R4. The correct answer is: - ⃝ 0, 1, 2, and 3
Transcribed Image Text:### Bitwise Operations in Assembly Language #### 7.3.1 - What bit positions (7 to 0) in R4 will be cleared when the following instruction is executed? ``` bic.b #11110000b, R4 ``` - ⃝ 0, 1, 2, 3, 4, 5, 6, and 7 - ⃝ 4, 5, 6, and 7 - ⃝ 0 - ⃝ 0, 1, 2, and 3 #### Explanation: The `bic` instruction stands for "bit clear". It performs a bitwise AND operation on the value in register R4 with the inverse of the immediate value provided (`#11110000b`). Here's the step-by-step analysis for the given operation: - The immediate value `11110000b` is binary for 240 in decimal. - Inverting `11110000b` gives us `00001111b`. - The `bic` operation will clear bits in R4 where the inverse value (`00001111b`) has a 1. Therefore, this operation will clear the bit positions 0, 1, 2, and 3 in register R4. The correct answer is: - ⃝ 0, 1, 2, and 3
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