What does the "jal" instruction do? O First saves the address of the next instruction in a user-specified register, and then jumps to the given address O First jumps to the given address, and then saves the address of the next instruction in the $ra register O First jumps to the given address, and then saves the address of the next instruction in a user-specified register O First saves the address of the next instruction in the $ra register, and then jumps to the given address

What does the "jal" instruction do? O First saves the address of the next instruction in a user-specified register, and then jumps to the given address O First jumps to the given address, and then saves the address of the next instruction in the $ra register O First jumps to the given address, and then saves the address of the next instruction in a user-specified register O First saves the address of the next instruction in the $ra register, and then jumps to the given address

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

What is the first action that the CPU does when the INT instruction is executed?
* H/W At a certain time, the simple computer registers contents the following data: PC = 1FFH, AR = B5CH, DR = 1234 H, AC = 6D97H, and IR = 08F5H. The memory contents at certain addresses are given below: (1) What is the instruction that will be fetched and executed? (2) instruction is executed. Show the binary operation that will be performed when the (3) end of the instruction cycle? Give the contents of the simple computer registers at the МЕMORY ADDRESS MEMORY DATA IN IN HEX. НЕХ. 1FF 7C48 B5C 5113 C48 A025 CD9 F517
When an instruction set is designed with a "backup" instruction for every other instruction that completes the same task, orthogonality has occurred. You can tell me if it's accurate or not.
What is the first action that the CPU does when the INT instruction is executed?
Orthogonality is the property of an instruction set design to have a "backup" instruction for every other instruction that accomplishes the same purpose as the original instruction. You are free to enlighten me as to whether or not it is true.
What may possible trigger a return to the instruction presently being performed in the case of an error?
After the ROL instruction is executed in the code sequence below, the final value for AL determines the values for the FLAGS. What is the value for the FLAGS? MOV AL, 1001_1100b ROL AL, 3 a. CF= 0, ZF= 0, SF= 1, AF= 1, OF= 0, PF= 1. b. CF= 1, ZF= 0, SF= 0, AF= 0, OF= 0, PF= 1. O C. CF= 1, ZF= 1, SF= 0, AF= 0, OF= 0, PF= 1. O d. CF= 0, ZF= 0, SF= 0, AF= 0, OF= 1, PF= 0.
After the instruction Idr ro, [r1] is executed, what is the content of ro? O A. The 8-bit value located at the memory address stored in r1 B. The memory address where r1 is stored O C. The 32-bit value located at the memory address stored in r1 O D. A copy of r1
Q2. Interface 4 digit displays (each digit is a 7-segment display) to the 80386DX microprocessor (32 bit data bus and 32 bit address bus) using 8255 PPI. The 8255 should function at I/O addresses that start at 200H. Then write a program to initialize the 8255 and multiplex the 4 digit display where the data, in 7-segment code, that is to be displayed is stored at memory location 2000H: 0100H.
The subject is assembly language - 8086 microprocessor
When an instruction set is designed with a "backup" instruction for every other instruction that completes the same task, orthogonality has occurred. You can tell me if it's accurate or not.
Can you please fill out the chart with a design instruction that would subtract a n operand he of in the main memory from the value store d in the accumulator registry. Thanks will thumbs up