7.104. The ac equivalent circuit for an amplifier is shown in Fig. P7.104.. Assume the capacitors have infinite value,R₁ = 10 kn, RG = 1 MQ, R₂ = 3.9 k2, and R3 = 33 kQ.. Calculate the voltage gain for the amplifier if the MOSFET Q-point is (2mA, 7.5 V). Assume K₁ = 1 mA/V² and λ = 0.015 V-¹.Figure P7.104C₁R₁www*SRGTwo-portViRDC₂R3

Small Signal Modelling rdS=VAID=1λID=1.015×2m=33.3kΩVoltage…

7.104. The ac equivalent circuit for an amplifier is shown in Fig. P7.104.. Assume the capacitors have infinite value, R₁ = 10 kN, RG = 1 MQ, R₂ = 3.9 kN, and R3 = 33 k.. Calculate the voltage gain for the amplifier if the MOSFET Q-point is (2 mA, 7.5 V). Assume K₁ = 1 mA/V² and λ = 0.015 V-¹. R₁ C₁ RG Two-port Rp C₂ R3

7.104. The ac equivalent circuit for an amplifier is shown in Fig. P7.104.. Assume the capacitors have infinite value, R₁ = 10 kN, RG = 1 MQ, R₂ = 3.9 kN, and R3 = 33 k.. Calculate the voltage gain for the amplifier if the MOSFET Q-point is (2 mA, 7.5 V). Assume K₁ = 1 mA/V² and λ = 0.015 V-¹. R₁ C₁ RG Two-port Rp C₂ R3

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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1. For the fixed-bias configuration of Fig. 7.75: a. Sketch the transfer characteristics of the device. b. Superimpose the network equation on the same graph. c. Determine In, and Vos d. Using Shockley's equation, solve for Ip, and then find Vps- Compare with the solutions of part (c). 1 MQ 1.5 V 14 V 1.8 ΚΩ IDQ + Vpso FIG. 7.75 pss= 12 mA Vp = -4 V
B : In the circuit of the figure shown. The Ge transistor is characterized by Vcc = 12V, V, = 2V ,Rc = 4KN, R, = 100KN ,B=50, ICeo = 0 and VcEsar = 0.2 V. %3D %3D Find the value of Rp that just results in saturation if: A- The capacitor is present. B- The capacitor is replaced with a short circuit Vcc RB Rc Rs Vs
2. For the self-bias configuration of Fig. 7.80 a. Sketch the transfer curve for the device. b. Superimpose the network equation on the same graph. c. Determine ID and VGS. d. Calculate VDS, VD, VG, and Vs. 18 V 1.5 kQ Dss = 10 mA V, =-4V Vase 1 MQ 750 n
7.2 Fixed-Bias Configuration 1. For the fixed-bias configuration of Fig. 7.75: a. Sketch the transfer characteristics of the device. b. Superimpose the network equation on the same graph. c. Determine Ip, and Vpsg d. Using Shockley's equation, solve for Ip, and then find Vpsg. Compare with the solutions of part (c). 14 V 1.8 kn IDQ Ipss = 12 mA Vpso Vp = -4 V 1 M2 1.5 V FIG. 7.75
ID = 6. For the self-bias configuration of Fig. 7.80: a. Sketch the transfer curve for the device. b. Superimpose the network equation on the same graph. c. Determine Ipo and VGSQ d. Calculate Vps, VD, VG, and Vs. *7. Determine Ip for the network of Fig. 7.80 using a purely mathematical approach. That is, establish a quadratic equation for Ip and choose the solution compatible with the network char- acteristics. Compare to the solution obtained in Problem 6. VGS IDSS (1 - Vass) ² Vp PROBLEMS Self-Bias Configuration 1 ΜΩ , + Vaso 18 V '1.5 ΚΩ IDss = 10 mA Vp = -4 V 750 £2 FIG. 7.80 1 ΜΩ VGSQ 12 V • 2.2 ΚΩ Ipe Ipss = 6 mA Vp = -6 V 11.6 ΚΩ 3 V FIG. 7.81 51
2. Textbook problem 7.52 (assuming a factor of 10 so the impedance of C₁ and C, can be negligible).
+Vcc 7.74. What is the voltage gain of the common-emitter amplifier in Fig. P7.10.? Assume BF = 135, Vcc= VEE = 10 V, R₁ = 20 kN, R₂ = 62 kN, Rc = 13 k, and Rg = 3.9 k. Rc Figure P7.10 VI www 1kQ2 R₂ R₁ RE l₁ C₂ VEE C3 R3 100 ΚΩ + vo
It explains what formula is used to solve the problem step by step and why that formula is used. Please explain in an easy to understand wayAlso, I would like you to explain how to solve the problem
7.101. The ac equivalent circuit for an amplifier is shown in Fig. P7.101.. Assume the capacitors have infinite value, R₁ = 502, R₂ = 4.7 kQ, Rc = 4.7 k2, and R3 = 10 km. Calculate the voltage gain for the amplifier if the MOSFET Q-point is (100 µA, 5 V). Assume K₁= 450 μA/V² and λ = 0.02 V-¹. Figure P7.101 R₁ Vi RG Rp R₂ Thévenin equivalent
In a fixed-target experiment with m1 = m2 = m, derive approximate expressions for Ecm in the following limiting cases: (a) K << mc2 and (b) K >> mc2 . Discuss your results in both cases
7.5k2 Q4 5 ΚΩ, Q₁ -15V +15V :5K2 Voz Q₂ 5KR -oVoz K₂Q3 1.2KS2 Consider the BJT differential amplifier on the left. The transistor parameters are: Bn = 180; VBE (on) = 0.65V; and VA = 60V. Do NOT ignore intrinsic output resistances. V03 (a) Calculate the differential gain Ad Va Vos = (b) Calculate the common-mode gain Acm Vem (c) Determine the output voltage Vos if v₁ = 2.015 sinct and v₂ = 1.985 sin wt. (d) Determine the differential-mode and common-mode input resistances.