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- For a two-tailed independent samples t test with a = 0.05 and N1 = 30 & N2 = 32, the critical value(s) should be t?The desired percentage of Sio, in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of Sio, in a sample is normally distributed with o = 0.32 and that x = 5.23. (Use a = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5? State the appropriate null and alternative hypotheses. Ho: u = 5.5 Hg: µ 2 5.5 Ho: H = 5.5 HaiH 5.5 = Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is not sufficient evidence to conclude that the true average percentage differs from the desired percentage. O Reject the null hypothesis. There is sufficient evidence to conclude that the true average percentage differs from the…6). A random sample of 90 observations produced a mean of x¯=21 from a population with a normal distribution and a standard deviation σ=4.1.
- 6.13.1.1)Given X=14.5% SD=3.4% N=25 90% CI for population mean is X.where Z=1.645 at 905 confidence =14.5±1.645 =14.5±1.12 =(13.38%,15.62%) We are 90% confident that the actual mean dividend yield lies between 13.38% and 15.62%. 3.1.2) 95% CI is X±Z where Z =14.5±1.96. =14.5±1.33 =(13.17%,15.83%) is the 95% Confidence interval Compare the 2 calculations above by means of a diagramA consumer group claims that the mean minimum time it takes for a sedan to travel a quarter mile is greater than 14.5 seconds. A random sample of 24 sedans has a mean minimum time to travel a quarter mile of 15.4 seconds and a standard deviation of 2.09 seconds. At α=0.01 is there enough evidence to support the consumer group's claim? Complete parts (a) through (d) below. Assume the population is normally distributed.
- The minimum sample size needed to estimate a population mean within 2 units with a 95% confidence when the population standard deviation equals 8 is A. 62 OB. 9 C. 8 O D. 61 A random sample of 64 observations has a mean of 30. The population variance is assumed to be 9. The 85.3% confidence interval estimate for the population mean (to the third decimal place) is O A. (28.369, 31.631) O B. (29.383, 30.617) O C. (29.456, 30.544) O D. (28.560, 31.440)The desired percentage of SiO₂ in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO₂ in a sample is normally distributed with = 0.32 and that x = 5.23. (Use a = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5? State the appropriate null and alternative hypotheses. O Ho: μ = 5.5 H₂:μ> 5.5 O Ho: μ = 5.5 H₂: μ = 5.5 ⒸHO: μ = 5.5 H₂:μ ≥ 5.5 O Ho: μ = 5.5 H₂: μ< 5.5 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) Z = P-value = State the conclusion in the problem context. O Do not reject the null hypothesis. There is not sufficient evidence to conclude that the true verage percentage differs from the desired percentage. O Reject the null hypothesis. There is not sufficient evidence to…In a tri-variate distribution: o1 = 3 o2 = 4 03 = 5 r23= 0.4 r31=0.6 r12=0.7 determine the regression of x1 on x2 and x3 if the variates are measured from their mean
- 12. Two independent samples are taken from two populations. Sample 1 has a mean of 12.8, a standard deviation of 2.3, and a sample size of 18. Sample 2 has a mean of 14.2, a standard deviation of 5.2, and a sample size of 23. This gives a standard error se(Ã1 — Ă2) = 1.212. A 95% confidence interval for the difference between the two means is: (A) (-2.00, -0.80). (B) (11.66, 13.94). (C) (-3.96, 1.16). (D) (-3.85, 1.05). (E) (-3.78, 0.98).The pulse rates of 176 randomly selected adult males vary from a low of 40 bpm to a high of 116 bpm. Find the minimum sample size required to estimate the mean pulse rate of adult males. Assume that we want 95% confidence that the sample mean is within 2 bpm of the population mean. Assume that o= 10.1 bpm, based on the value s = 10.1 bpm from the sample of 176 male pulse ratesA random sample of 130 observations produced a mean of I = 23.5 and a standard deviation s = 2.16. (a) Find a 90% confidence interval for u (b) Find a 95% confidence interval for u (c) Find a 99% confidence interval for u